Quantitative Aptitude - MCQ Practice Questions

Using compound growth: 100(1+r)³ = 160. (1+r)³ = 1.6. 1+r = 1.6^($\frac{1}{3}$) ≈ 1.1696. r ≈ 16.96% ≈ 16.5%.

Let n = previous innings. 40n + 65 = 45(n+1). 40n + 65 = 45n + 45. 20 = 5n. n = 4.

Total distance = 40 + 60 + 100 = 200 km. Time for first = $\frac{40}{20}$ = 2 hours. Time for second = $\frac{60}{30}$ = 2 hours. Time for third = $\frac{100}{50}$ = 2 hours. Total time = 6 hours. Average speed = $\frac{200}{6}$ = 33.33 km/h.

Let boys = 3x, girls = 2x. Total weight = (3x × 60) + (2x × 55) = 180x + 110x = 290x. Average = 290x / 5x = 58 kg.

To find the average work rate per day for the remaining workers, we must calculate each worker's individual rate, then find the combined rate after A leaves.

Step 1: Calculate individual work rates

Worker A completes the job in 12 days, so A's rate = $\frac{1}{12}$ job/day

Worker B completes the job in 15 days, so B's rate = $\frac{1}{15}$ job/day

Worker C completes the job in 20 days, so C's rate = $\frac{1}{20}$ job/day

Step 2: Find the combined rate of all three workers

Finding the LCM of 12, 15, and 20:

Step 3: Calculate work done in first 2 days

In 2 days, all three workers complete:

This information establishes context, but the question asks for the average rate of remaining workers (B and C) after A leaves.

Step 4: Find average work rate of remaining workers (B and C)

Number of remaining workers = 2

**Answer: The average work rate per day for the remaining workers is $\frac{7}{120}$ (Option A)**