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Electrical Engg (EEE)

Electrical machines, power systems, circuits

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Topics in Electrical Engg (EEE)

All Circuit Analysis 100 Electrical Machines 100 Power Systems 100 Control Systems 100 Power Electronics 100 Electrical Measurements 40

Q.1 Hard Electrical Measurements

A light intensity meter using a photocell shows reading of 500 lux. If the luminous intensity of the source is constant, what happens to the reading when distance is doubled?

A Becomes 250 lux

B Becomes 125 lux

C Becomes 1000 lux

D Remains 500 lux

Correct Answer: B. Becomes 125 lux

EXPLANATION

Illuminance follows inverse square law: E ∝ 1/d²; when distance doubles, illuminance becomes 1/4th: 500/4 = 125 lux.

Test

Q.2 Easy Electrical Measurements

In a Wheatstone bridge for resistance measurement, if R₁ = 100 Ω, R₂ = 50 Ω, R₃ = 200 Ω, what should be R₄ for balance?

A 50 Ω

B 100 Ω

C 150 Ω

D 200 Ω

Correct Answer: B. 100 Ω

EXPLANATION

At balance: R₁/R₂ = R₃/R₄; R₄ = (R₂ × R₃)/R₁ = (50 × 200)/100 = 100 Ω.

Test

Q.3 Medium Electrical Measurements

What is the main limitation of analog instruments in automated data acquisition systems?

A Lower measurement accuracy

B Inability to provide direct digital output for computer interfacing

C Higher temperature stability

D Better frequency response

Correct Answer: B. Inability to provide direct digital output for computer interfacing

EXPLANATION

Analog instruments cannot directly interface with digital computers; they require ADC conversion for data acquisition systems.

Test

Q.4 Medium Electrical Measurements

In a potentiometer method for EMF comparison, if standard cell EMF is 1.018 V with 106.4 cm length, and unknown cell requires 107.8 cm, what is unknown EMF?

A 1.026 V

B 1.031 V

C 1.018 V

D 1.035 V

Correct Answer: B. 1.031 V

EXPLANATION

E₂/E₁ = L₂/L₁; E₂ = (107.8/106.4) × 1.018 ≈ 1.031 V.

Test

Q.5 Easy Electrical Measurements

A pressure transducer has sensitivity of 0.5 V/bar. If input pressure varies from 0-10 bar, what is the output voltage range?

A 0-2.5 V

B 0-5 V

C 0-10 V

D 0-50 V

Correct Answer: B. 0-5 V

EXPLANATION

Output voltage = Sensitivity × Pressure = 0.5 × 10 = 5 V for maximum pressure of 10 bar.

Test

Q.6 Medium Electrical Measurements

In a LVDT (Linear Variable Differential Transformer), when the core is at null position, what happens to the output voltage?

A Maximum positive voltage

B Minimum (approximately zero)

C Maximum negative voltage

D Voltage equals excitation voltage

Correct Answer: B. Minimum (approximately zero)

EXPLANATION

At null position in LVDT, the core is centered, and secondary voltages from both coils cancel out, resulting in zero or minimum output.

Test

Q.7 Easy Electrical Measurements

Which bridge circuit is specifically designed to measure inductance with small resistance?

A Maxwell bridge

B Hay bridge

C Owen bridge

D Schering bridge

Correct Answer: A. Maxwell bridge

EXPLANATION

Maxwell bridge is used for measuring inductance (especially with small resistance) in industrial and laboratory applications.

Test

Q.8 Medium Electrical Measurements

A standard cell has an EMF of 1.0186 V at 20°C with temperature coefficient of -0.0004 V/°C. What will be its EMF at 25°C?

A 1.0186 V

B 1.0170 V

C 1.0180 V

D 1.0202 V

Correct Answer: B. 1.0170 V

EXPLANATION

EMF at 25°C = 1.0186 - 0.0004 × (25-20) = 1.0186 - 0.002 = 1.0166 ≈ 1.0170 V.

Test

Q.9 Hard Electrical Measurements

In a three-phase power measurement using two-wattmeter method, the power factor can be determined from which relationship?

A tan(φ) = √3(W₁ - W₂)/(W₁ + W₂)

B cos(φ) = (W₁ + W₂)/√3VIL

C sin(φ) = (W₁ - W₂)/(W₁ + W₂)

D Power factor = (W₁ + W₂)/(W₁ - W₂)

Correct Answer: A. tan(φ) = √3(W₁ - W₂)/(W₁ + W₂)

EXPLANATION

For two-wattmeter method in three-phase systems: tan(φ) = √3(W₁ - W₂)/(W₁ + W₂), used to calculate power factor.

Test

Q.10 Hard Electrical Measurements

A strain gauge has gauge factor of 2.1 and resistance change of 5 Ω for a strain of 0.001. What is the original resistance of the gauge?

A 2300 Ω

B 2381 Ω

C 2500 Ω

D 2000 Ω

Correct Answer: B. 2381 Ω

EXPLANATION

Gauge factor = (ΔR/R₀)/strain; 2.1 = 5/(R₀ × 0.001); R₀ = 5/(2.1 × 0.001) ≈ 2381 Ω.

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