Quantitative Aptitude - MCQ Practice Questions

Step 1: Profit = 25% of ₹400 = 0.25 × 400 = ₹100.

Step 2: Selling Price = Cost Price + Profit = 400 + 100 = ₹500.

Step 3: Let Marked Price = M.

After 15% discount: M × (1 - 0.15) = 500, so M × 0.85 = 500, M = $\frac{500}{0}$.85 = ₹588.24 (approximately).

Therefore, option A is correct.

New price = 1.25P. For constant expenditure: New consumption = $\frac{1}{1}$.25 = 0.8. Reduction = 20%.

SI = (50,000 × 10 × T)/100. 15,000 = 5000T. T = 3 years.

CP = 100, MP = 180, SP = 144 (for 44% profit). Discount = 180 - 144 = 36. Discount% = ($\frac{36}{180}$) × 100 = 20%.

Initial price × 1.16 = 465. Initial price = $\frac{465}{1}$.16 = 400.

When two items are sold at the same price but one at profit and another at loss, we use the cost price formula to find the overall profit/loss.

Step 1: Find Cost Price of Item 1 (25% profit)

If selling price is ₹900 at 25% profit, then:

Step 2: Find Cost Price of Item 2 (25% loss)

If selling price is ₹900 at 25% loss, then:

Step 3: Calculate Total Cost Price and Total Selling Price

Step 4: Find Overall Profit/Loss

Selling price (SP) of each item = ₹900

First item: 25% profit

CP

1

​

=

125

900×100

​

=₹720

Second item: 25% loss

CP

2

​

=

75

900×100

​

=₹1200

Total Cost Price

720+1200=₹1920

Total Selling Price

900+900=₹1800

Loss

1920−1800=₹120

Loss Percentage

1920

120

​

×100=6.25%

Therefore, the overall result is a loss of 6.25%.

Answer: Overall loss is ₹120 (Option C) ₹120 loss

Let C = 100. B = 110. A = 1.2 × 110 = 132. A is 32% more than C.

For 20% gain at ₹1,200: CP = 1,$\frac{200}{1}$.20 = ₹1,000. For 20% loss at ₹1,200: CP = 1,$\frac{200}{0}$.80 = ₹1,500. Total CP = ₹2,500, Total SP = ₹2,400. Loss = ₹100. Loss% = ($\frac{100}{2}$,500) × 100 = 4%

# Depreciation Problem — Compound Decay

When a value depreciates by a fixed percentage annually, we use the compound depreciation formula: $V_n=V_0(1-r{)}^n$, where $V_0$ is the initial value, $r$ is the depreciation rate, and $n$ is the number of years.

Step 1: Identify the given values

Initial value: $V_0=₹8,00,000$

Annual depreciation rate: $r=15\%=0.15$

Time period: $n=2$ years

Step 2: Set up the depreciation formula

After each year, the car retains $(1-0.15)=0.85$ of its previous value.

Step 3: Substitute values

Step 4: Calculate step-by-step

First, find $(0.85{)}^2$:

Then multiply by the initial value:

Answer: The car's value after 2 years will be ₹5,78,000 (Option A)

Let original number = x. After 20% increase: 1.20x. After 15% decrease: 1.20x × 0.85 = 510. 1.02x = 510. x = 500

Let B = 100, A = 75. B is more than A by 25 on base of 75 = ($\frac{25}{75}$) × 100 = 33.33%