Quantitative Aptitude - MCQ Practice Questions

This problem uses the relationship between price reduction, quantity purchased, and total expenditure. We'll set up an equation comparing purchases before and after the price change.

Step 1: Define variables

Let the original price of sugar be $P$ per kg.

After a 15% reduction, the new price is:

Step 2: Set up the quantity equation

With ₹510, the customer can buy:

The difference is 3 kg:

Step 3: Simplify the equation

Factor out 510:

Step 4: Solve for P

Verification: At ₹30/kg: buys $\frac{510}{30}=17$ kg. At ₹25.50/kg: buys $\frac{510}{25.50}=20$ kg. Difference = 3 kg. ✓

Answer: The original price was ₹30 per kg (Option A)

Net change = 20 - 10 - (20×10)/100 = 10 - 2 = 8% increase

Let income = 100, savings = s, expenditure = 100-s. New income = 112, new savings = 1.2s, new expenditure = 1.08(100-s). 112 = 1.2s + 1.08(100-s). Solving: s = 20

Let CP = 100. MP = 160. SP = 160 × 0.75 = 120. Profit% = 20%

Population in 2023 = 5,00,000 × 0.92 = 4,60,000. Population in 2024 = 4,60,000 × 1.10 = 5,06,000

Profit:CP = 3:5. So if CP = 5, Profit = 3. Profit% = ($\frac{3}{5}$) × 100 = 60%

If original price = x, then 0.82x = 410. x = $\frac{410}{0}$.82 = ₹500

After 10% discount: 800 × 0.90 = ₹720. After 5% discount: 720 × 0.95 = ₹684

CP = 600, MP = 600 × 1.40 = 840, SP = 840 × 0.85 = 714. Profit% = (714-600)/600 × 100 = 19%

Let C = 100, B = 110, A = 110 × 1.20 = 132. A is 32% more than C

To find how many additional days are needed, we use the relationship between work completed and time, where work rate remains constant.

Step 1: Find the daily work rate

If 30% of the job is completed in 6 days, the daily rate is:

Step 2: Calculate total days needed for 80% of the job

At a constant rate of 5% per day, the time to complete 80% is:

Step 3: Find additional days needed

The worker has already spent 6 days on the first 30%. Additional days required:

Answer: The worker needs 10 more days to complete 80% of the job (Option A)

A's rate = $\frac{1}{12}$, B's rate = $\frac{1}{15}$. Combined = $\frac{1}{12}$ + $\frac{1}{15}$ = $\frac{9}{60}$ = $\frac{3}{20}$. In 3 min = 3 × $\frac{3}{20}$ = $\frac{9}{20}$ filled. Remaining = $\frac{11}{20}$. Only A works = ($\frac{11}{20}$)/($\frac{1}{12}$) = ($\frac{11}{20}$) × 12 = 6.6 ≈ 5 minutes (approx)

Milk = ($\frac{3}{5}$) × 60 = 36L, Water = 24L. For 1:1 ratio, milk = water, so need 36L water. Water to add = 36 - 24 = 12L

Let CP = 100, MP = 150. SP = 150 × 0.70 = 105. Profit = 5%. Profit% = 5%

x% of 480 = 72, so x = 15%. For 96: ($\frac{96}{480}$) × 100 = 20%