Which type of reactor provides the best conversion for a reversible exothermic reaction?
Answer: C
PFR with heat removal maintains optimal temperature profile and continuous removal of products, favoring forward reaction equilibrium
Q.2Medium
In a CSTR operating at steady state, if residence time is doubled and inlet concentration remains constant, how does conversion change for a first-order reaction?
Answer: B
For CSTR: X = kτ/(1+kτ). Increasing τ increases conversion for first-order reactions
Q.3Medium
For parallel reactions A→B and A→C, the selectivity of B over C is defined as:
Answer: A
Selectivity = rate of desired product formation/rate of undesired product formation
Q.4Medium
In a catalytic reaction, which parameter does NOT affect the rate of reaction?
Answer: C
Catalyst doesn't change ΔG or equilibrium position; it only lowers Eₐ. ΔG determines feasibility, not rate
Q.5Medium
For the reaction 2A → B, if initial concentration of A is 2 mol/L and concentration after 5 minutes is 1 mol/L, calculate rate constant (assuming second-order):
Answer: A
For 2nd order: 1/[A] = 1/[A]₀ + kt; 11 = 21 + k(5); k = 0.1 L/(mol·min)
Advertisement
Q.6Medium
The Damköhler number (Da) in chemical reactor design represents:
Answer: B
Da = kτ = (reaction rate constant × residence time), dimensionless number indicating reaction extent
Q.7Medium
In enzyme catalysis, what does the Michaelis-Menten constant (K_m) represent?
Answer: A
K_m represents substrate concentration [S] at which reaction velocity = V_max/2
Q.8Medium
For an exothermic reaction in an adiabatic reactor, what happens to the reaction rate as conversion increases?
Answer: C
Adiabatic reactor: no heat removal; exothermic reaction raises temperature, increasing k and hence rate
Q.9Medium
For autocatalytic reactions, which reactor gives highest conversion at equilibrium?
Answer: D
Equilibrium conversion is thermodynamically determined and independent of reactor type
Q.10Medium
For a second-order reaction A+B→C with equal initial concentrations of 1 mol/L, if the rate constant is 0.5 L/(mol·min), what is the time required for 50% conversion?
Answer: A
For second-order reaction with CA0 = CB0: 1/CA - 1/CA0 = kt. At 50% conversion, CA = 0.5. So (01.5 - 11) = 0.5×t gives t = 2 minutes
Q.11Medium
In a CSTR operating at steady state, the space time (τ) for a first-order reaction is 5 minutes. What is the conversion if k = 0.2 min⁻¹?
Answer: B
For CSTR: τ = (CA0 - CA)/(kCA) = X/(k(1-X)). Solving: 5 = X/(0.2(1-X)) gives X = 0.667 or 66.7%
Q.12Medium
Which of the following reactor types is most suitable for producing fine chemicals where precise temperature control is critical?
Answer: A
Batch reactors provide excellent temperature control through jacket systems and are ideal for fine chemicals production where reaction conditions are critical and batch processing is economical
Q.13Medium
In the Arrhenius equation k = A×e^(-Ea/RT), if the activation energy is 80 kJ/mol and temperature increases from 300K to 310K, what is the approximate ratio of rate constants k2/k1?
Answer: B
Using ln(k2/k1) = (Ea/R)×(1/T1 - 1/T2) = (880000.314)×(3001 - 3101) ≈ 0.693, so k2/k1 ≈ 2.0
Q.14Medium
In a reversible elementary reaction A ⇌ B with forward rate constant kf = 0.1 s⁻¹ and reverse rate constant kr = 0.02 s⁻¹, what is the equilibrium constant K?
Answer: B
For reversible reactions, K = kf/kr = 0.01.02 = 5.0. This represents the ratio of forward to reverse rate constants at equilibrium
Q.15Medium
Which catalyst property is most important for industrial applications requiring high selectivity in parallel reactions?
Answer: B
Pore size distribution determines which reactants/products can access active sites, while active site specificity ensures desired reaction pathway is favored in parallel reactions
Q.16Medium
For an exothermic reaction, operating a CSTR at higher conversion requires:
Answer: C
Exothermic reactions generate heat; to achieve higher conversion without temperature runaway, external cooling must be provided to maintain reactor temperature within safe operating limits
Q.17Medium
In industrial polymerization reactions, what is the primary role of chain termination reactions?
Answer: B
Chain termination by combination or disproportionation determines when polymer chains stop growing, directly controlling final molecular weight and its distribution
Q.18Medium
For a reaction A + B → C where both reactants are supplied in stoichiometric ratio, if reaction order with respect to A is 1 and B is 1, and initial concentrations are each 2 mol/L, the integrated rate law shows conversion X varies as:
Answer: A
For second-order reactions with equal initial concentrations CA0 = CB0, the integrated form simplifies to: CA = CA0/(1+kCA0×t), leading to pseudo-first order kinetics behavior
Q.19Medium
Which of the following statements about residence time distribution (RTD) in reactors is incorrect?
Answer: A
RTD in plug flow reactors is independent of flow rate only for ideal reactors without dispersion. In real reactors, axial dispersion effects vary with flow rate.
Q.20Medium
For a first-order consecutive reaction A → B → C where k₁ = 0.1 min⁻¹ and k₂ = 0.05 min⁻¹, the maximum concentration of intermediate B occurs at approximately:
Answer: C
For consecutive reactions, [B]max occurs at t_max = ln(k₁/k₂)/(k₁-k₂) = ln(2)/0.05 = 13.86 minutes