For the reaction 2NO + Cl₂ → 2NOCl, the rate law is found to be Rate = k[NO]²[Cl₂]. The order with respect to NO is:
Answer: B
The exponent of [NO] in the rate law is 2, making the reaction second order with respect to NO
Q.22Medium
In the decomposition of N₂O₅, the rate constant at 320 K is 1.7 × 10⁻⁵ s⁻¹ and at 330 K is 5.0 × 10⁻⁵ s⁻¹. The activation energy is approximately:
Answer: A
Using ln(k₂/k₁) = (Ea/R)(1/T₁ - 1/T₂): ln(5.10.7) = (Ea/8.314)(3201 - 3301), solving gives Ea ≈ 50 kJ/mol
Q.23Easy
A zero-order reaction has an initial concentration of 0.5 M and rate constant k = 0.02 M/s. The time taken for the concentration to reduce to 0.1 M is:
Answer: C
For zero-order reaction: [A]₀ - [A]ₜ = kt. So 0.5 - 0.1 = 0.02 × t, giving t = 20 s
Q.24Medium
The half-life of a first-order reaction is independent of the initial concentration. If t₁/₂ = 30 minutes for a reaction, the time for the concentration to reduce to 41th of initial value is:
Answer: C
For first-order reaction, [A]ₜ = [A]₀(21)^(t/t₁/₂). For [A]ₜ = 41[A]₀, we need (21)^(t/30) = 41, so t/30 = 2, giving t = 60 minutes
Q.25Easy
In a reaction mechanism with fast pre-equilibrium followed by slow step, which statement is correct?
Answer: A
The rate-determining step (slowest step) controls the overall reaction rate, regardless of how many fast equilibrium steps precede it
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Q.26Easy
For the reaction: A + B → Products with Rate = k[A][B]², what is the overall order of reaction?
Answer: C
Overall order = sum of exponents in rate law = 1 + 2 = 3 (third order reaction)
Q.27Hard
The rate constant for a reaction at 298 K is 2 × 10⁻⁵ s⁻¹ with Ea = 80 kJ/mol. What is the frequency factor (A) if rate = Ae^(-Ea/RT)?
In enzyme catalysis, the Michaelis constant (Km) represents:
Answer: B
Km is a characteristic constant for an enzyme-substrate pair, representing substrate concentration when v = Vmax/2
Q.33Easy
For a reaction with rate law Rate = k[A]⁰[B]¹, if [B] is increased 4 times while [A] remains constant, the rate increases by:
Answer: B
Since the reaction is first-order in B and zero-order in A, Rate ∝ [B]. Increasing [B] by 4 times increases Rate by 4 times
Q.34Hard
In the reaction mechanism: (1) A + B ⇌ AB (fast), (2) AB + C → ABC (slow), the order predicted from this mechanism is:
Answer: C
Rate = k₂[AB][C]. From fast equilibrium: [AB] = K₁[A][B]. So Rate = k₂K₁[A][B][C], making it third-order overall
Q.35Medium
The temperature coefficient (Q₁₀) for a reaction is 2.5. If the rate at 300 K is r, then the rate at 320 K is approximately:
Answer: B
Q₁₀ = rate at (T+10)/rate at T. For 300K to 320K (two 10K intervals), rate = r × 2.5² = 6.25r
Q.36Easy
For the reaction A → B, experimental data shows: [A] vs time is a straight line. This indicates:
Answer: B
A straight line in [A] vs time plot indicates [A] = [A]₀ - kt, which is the integrated rate law for zero-order reactions
Q.37Hard
In the complex reaction: A + B → I (fast equilibrium), I + B → C (slow), the rate law derived from this mechanism is:
Answer: B
Rate = k₂[I][B]. From equilibrium: [I] = K₁[A][B]. Therefore: Rate = k₂K₁[A][B]², which is second-order in B
Q.38Medium
The pre-exponential factor (A) in the Arrhenius equation is related to:
Answer: C
The pre-exponential factor accounts for collision frequency, proper orientation (steric factor), and the Maxwell-Boltzmann energy distribution of molecules
Q.39Easy
For an elementary reaction: A + A + B → Products, the rate law is:
Answer: B
For elementary reactions, the rate law is determined by the stoichiometry: Rate = k[A]²[B], as 2 A molecules and 1 B molecule participate
Q.40Easy
For the reaction 2NO + O₂ → 2NO₂, the rate law is Rate = k[NO]²[O₂]. What is the overall order of reaction?
Answer: C
Overall order = sum of exponents in rate law = 2 + 1 = 3 (third order)