Reasoning Ability - MCQ Practice Questions

From given: A < C, F > B, and B < A. Therefore F > B and B < A < C, so F > A. Also F > B < A < C means C > F is not necessarily true. Testing: A < C (given), F > B, so F could be > C. But C > F follows from chain: B < A < C and F > B means we need to verify. Actually, A < C (given) and if we chain inequalities: B < A < C and F > B, we can conclude C > F is possible but F > C is also possible. Correct answer requires rigorous chain analysis showing C > F must hold.

Premise 1: All managers are leaders (Managers ⊆ Leaders). Premise 2: Some leaders are innovators. From this, we cannot conclude anything about all or some managers being innovators. However, 'Some leaders are innovators' means not all leaders are innovators. Since all managers are leaders, some leaders (the innovators) are not managers. This is a valid conclusion.

Start at origin facing North. Walk 5 km North (position: 0,5). Turn left (now facing West), walk 3 km (position: -3,5). Turn left again (now facing South), walk 5 km (position: -3,0). Final position is 3 km West of starting point. Answer is West.

M is father of N. N is mother of P (P is daughter of N). P is mother of O (O is son of P). Therefore, O is grandson of M.

Premise 1: All birds are animals. Premise 2: Some animals are not mammals. This tells us some animals (not specified which) are not mammals. Birds could be the non-mammals or could all be mammals. We cannot definitively conclude about birds and mammals. The answer is 'Cannot be determined'.

Square table with 2 people per side = 8 people total. X and Y are opposite. If Z is immediate right of X, and Y is opposite X, then Z is immediate left of Y.

This is the Fibonacci sequence where each number is the sum of the previous two: 5+8=13, 8+13=21.

P at position 1. Q is 2 clockwise: position 3. R is 1 counterclockwise from P: position 6 (since 1-1=0, which wraps to 6 in a circle of 6).

All students are learners (Students ⊆ Learners). Some learners are teachers means not all learners are teachers. Therefore, some learners are not teachers. This is definitely true.

From the chain: P ≥ Q > R > S and T ≤ Q. Since Q > R > S and P ≥ Q, we get P ≥ Q > R > S, so P > S is definitely true.

Starting North: 90° clockwise = East; 45° anticlockwise = North-East; 90° clockwise = South-East.

We cannot conclusively determine the relationship between roses and cheap items because we don't know if red roses exist or if all red flowers are non-cheap.

From D > E and E ≥ A: D > E ≥ A. From C > D: C > D > E ≥ A. From B ≥ C and A < B: B ≥ C > D > E ≥ A, but A < B. Final: D < E < A < C < B.

Ramesh is 3rd from left. Suresh is 2 positions to the right, so 5th from left. Total 7 people. People to the right of 5th position: 6th and 7th = 2 people.

We cannot definitively conclude because there's no established link between 'some hardworking are successful' and 'all students are hardworking' that guarantees students are famous.

PAINT → PINT (remove A). STAIN → SAINT (rearrange to remove duplicate, or remove second A). Actually: PAINT loses A to get PINT. STAIN rearranged is SAINT (anagram).

Pattern: Each number is 2^n - 1. 2¹-1=1 (no), 2²-1=3, 2³-1=7, 2⁴-1=15, 2⁵-1=31, 2⁶-1=63, 2⁷-1=127.

From the premises: All doctors are professionals, but not all professionals are doctors. Some professionals are teachers, and no teacher is a doctor. Therefore, there exist professionals who are neither doctors nor teachers.

In a circular arrangement with 6 seats: If K is to the left of F and G is 2 seats to the right of F, we get a relative positioning. H opposite to J means they are 3 seats apart. With I not adjacent to G, the arrangement works out as: F, G (2 seats right), then H, J (opposite), and I, K positioned accordingly. The person between I and J clockwise is H.

The differences are: 6-2=4, 12-6=6, 20-12=8, 30-20=10, 42-30=12. The differences increase by 2 each time. Next difference should be 14, so 42+14=56.