Practice <strong>NEET UG Physics</strong> MCQ questions covering Mechanics, Thermodynamics, Waves & Optics, Modern Physics, Electricity & Magnetism, and Electromagnetic Induction. Aligned with NCERT Class 11 & 12 Physics syllabus.
A car accelerates uniformly from rest at 5 m/s². What distance does it cover in 6 seconds?
Answer: C
Using s = ut + ½at², where u = 0, a = 5 m/s², t = 6s: s = 0 + ½(5)(36) = 90 m
Q.22Easy
A stone is thrown upward with velocity 30 m/s. What is its velocity when it returns to the same level? (g = 10 m/s²)
Answer: C
By conservation of energy and kinematics, the stone returns with the same speed but opposite direction: 30 m/s downward
Q.23Easy
A car moving at 20 m/s comes to rest in 5 seconds with uniform deceleration. The deceleration is:
Answer: B
Using v = u + at: 0 = 20 + a(5), a = -4 m/s². Deceleration = 4 m/s²
Q.24Easy
A particle of mass 2 kg moving with velocity 10 m/s is acted upon by a constant force in the direction of motion for 5 seconds. If the final velocity is 20 m/s, the magnitude of force is:
Answer: B
Using v = u + at: 20 = 10 + a(5), a = 2 m/s². F = ma = 2×2 = 4 N
Q.25Easy
A train accelerates uniformly from rest. If it covers 100 m in the first 10 seconds, what is its acceleration?
Answer: B
Using s = ut + ½at², where u = 0, s = 100 m, t = 10 s. Therefore, 100 = 0 + ½a(100), giving a = 2 m/s²
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Q.26Easy
Which of the following is NOT an inertial reference frame?
Answer: C
An inertial frame has zero acceleration. A rotating frame undergoes centripetal acceleration, making it non-inertial. All others have constant velocity (zero acceleration).
Q.27Easy
A person pushes a box on a horizontal surface with a force of 50 N. If the box moves with constant velocity, what is the friction force?
Answer: C
For constant velocity, acceleration = 0. By Newton's first law, net force = 0. Therefore, friction force must equal applied force = 50 N.
Q.28Easy
A 2 kg mass is subjected to forces of 3 N (east) and 4 N (north). What is the magnitude of acceleration?
Answer: C
Net force = √(3² + 4²) = 5 N. Using F = ma, a = 25 = 2.5 m/s²
Q.29Easy
A book rests on a table. The normal force on the book is 10 N. What is the weight of the book? (g = 10 m/s²)
Answer: B
At rest, normal force equals weight. N = mg, 10 = m × 10, therefore m = 1 kg
Q.30Easy
A car of mass 1000 kg experiences friction of 2000 N while moving. If the engine provides 5000 N of force, what is the net acceleration?
Answer: B
Net force = 5000 - 2000 = 3000 N. Using F = ma, a = 10003000 = 3 m/s²
Q.31Easy
An object is thrown vertically upward with initial velocity 20 m/s. At what time does it reach maximum height? (g = 10 m/s²)
Answer: B
At maximum height, v = 0. Using v = u - gt, 0 = 20 - 10t, therefore t = 2 s
Q.32Easy
A body of mass 5 kg is moving with a velocity of 10 m/s. What force is required to stop it in 2 seconds?
Answer: A
Using F = ma, where a = (v-u)/t = (0-10)/2 = -5 m/s². Therefore F = 5 × 5 = 25 N
Q.33Easy
Two forces of 12 N and 5 N act on a body. The maximum resultant force possible is:
Answer: B
Maximum resultant occurs when forces act in the same direction: R = 12 + 5 = 17 N
Q.34Easy
A car accelerates uniformly from rest and covers 100 m in 5 seconds. What is its acceleration?
Answer: A
Using s = ut + ½at², where u = 0, s = 100 m, t = 5 s: 100 = 0 + ½a(25), a = 8 m/s²
Q.35Easy
A ball is thrown vertically upward with an initial velocity of 20 m/s. How long does it take to reach maximum height? (g = 10 m/s²)
Answer: B
At maximum height, v = 0. Using v = u - gt: 0 = 20 - 10t, so t = 2 s
Q.36Easy
An object of mass 8 kg is on a horizontal surface with coefficient of kinetic friction 0.25. What is the friction force when the object is moving? (g = 10 m/s²)
Answer: B
f = μN = μmg = 0.25 × 8 × 10 = 20 N
Q.37Easy
Which statement best describes Newton's third law of motion?
Answer: B
Newton's third law states that for every action, there is an equal and opposite reaction force.
Q.38Easy
A system absorbs 500 J of heat and does 200 J of work on surroundings. What is the change in internal energy?
Answer: A
By first law: ΔU = Q - W = 500 - 200 = 300 J (where W is work done by system)
Q.39Easy
The entropy of an isolated system can never:
Answer: B
According to the second law of thermodynamics, entropy of an isolated system always increases or remains constant, never decreases.
Q.40Easy
In an isothermal process for an ideal gas, which quantity remains constant?
Answer: C
In isothermal process, temperature is constant. For ideal gas, internal energy U depends only on temperature, so U remains constant.
