Placement Papers - MCQ Practice Questions

The Internet Layer (Layer 3) handles IP addresses and routing. Transport Layer (Layer 4) handles ports.

Average speed = Total Distance / Total Time. Distance one way = 240 km. Time from A to B = $\frac{240}{60}$ = 4 hours. Time from B to A = $\frac{240}{40}$ = 6 hours. Total Distance = 480 km, Total Time = 10 hours. Average Speed = $\frac{480}{10}$ = 48 km/h.

Let the 4th number be x. Then 5th number = previous number + x. If 5th = 20 and 6th = 32, then 6th = 5th + 5th_previous, so 32 = 20 + (5th_previous). Therefore, 5th_previous = 12. Since 5th_previous is the 4th number, the answer is 12.