SSC CGL / CHSL / MTS - MCQ Practice Questions

Grandfather's only son = her father. Father's son = her brother

Minute hand at 3 (90°). Hour hand moves 0.5° per minute, so at 15 min: 90 + 7.5 = 97.5°. Difference = 97.5 - 90 = 7.5°

Speed = $\frac{150}{15}$ = 10 m/s = 10 × 3.6 = 36 km/h

Total work = 12 × 9 = 108 man-days. With 18 men: $\frac{108}{18}$ = 6 days

Let B = x. Then A = x+5, C = x+3. (x+5) + x + (x+3) = 35. 3x + 8 = 35. x = 9. A = 14 years

Sum of alphabetical positions: A(1)+P(16)+P(16)+L(12)+E(5)=50... Using alternate logic of position values, ORANGE=O(15)+R(18)+A(1)+N(14)+G(7)+E(5)=60+31=91

# Solution: Relationship Puzzle

This is a relationship tracking problem where we work backwards through family connections to identify who Arun is referring to.

## Step 1: Identify "My Mother's Only Son"

Arun states: "She is the mother of my mother's only son"

First, let's determine who Arun's mother's only son is:

## Step 2: Work Backwards to "She"

Now we reframe the statement:

## Step 3: Verify the Logic

Let's confirm by checking the family tree:

## Step 4: Eliminate Other Options

Answer: Arun is referring to his mother (Option A)

In 12 hours, hour and minute hands overlap 11 times. In 24 hours, they overlap 22 times

Each letter is shifted forward by 1: P→Q, E→F, N→O, C→D, I→J, L→M. Applying to GARDEN: G→H, A→B, R→S, D→E, E→F, N→O = HBSEOF

From given: E < D < C and B < A < D. So C > D > A and C > E. Therefore C is tallest

First letters: J, K, L, M, N (increment by 1). Numbers: 2, 4, 6, 8, 10 (increment by 2). Last letters: Z, X, V, T, R (decrement by 2 in alphabet)

Ratio 2:3:4, if 4x=12, then x=3. Capacities: 6, 9, 12. Total = 27 liters