SSC CGL / CHSL / MTS - MCQ Practice Questions

Sum = Average × Number of values = 24 × 5 = 120

Boys:Girls = 3:4. If boys = 12, then 3 units = 12, so 1 unit = 4. Girls = 4 × 4 = 16

25% of 480 = ($\frac{25}{100}$) × 480 = 120

Speed = Distance/Time = $\frac{360}{6}$ = 60 km/h

40% of x = 240 → ($\frac{40}{100}$) × x = 240 → x = 600

Profit = 1080 - 900 = 180. Profit% = ($\frac{180}{900}$) × 100 = 20%

2(1)² + 3(1) - 5 = 2 + 3 - 5 = 0. So x = 1 is a solution.

SI = (P × R × T)/100 = (2000 × 8 × 3)/100 = 480

Let numbers be 5x and 8x. Difference: 8x - 5x = 24 → 3x = 24 → x = 8. Larger = 8(8) = 64

Total spent = 30% + 40% = 70%. Remaining = 100% - 70% = 30%

23 ÷ 5 = 4 remainder 3. (or 23 = 5×4 + 3)

Area = Length × Breadth → 96 = 12 × B → B = 8 cm

A = P(1 + R/100)^T = 1000(1.1)² = 1000 × 1.21 = 1210

A's rate = $\frac{1}{15}$, B's rate = $\frac{1}{10}$. Combined rate = $\frac{1}{15}$ + $\frac{1}{10}$ = $\frac{5}{30}$ = $\frac{1}{6}$. Time = 6 days

Let the total volume of the mixture be $10x$ liters, so initially:

Step 1: Remove 10 liters of the mixture.

The removed mixture has the same 7:3 ratio, so it contains $\frac{7}{10}\cdot 10=7$ liters of milk and $\frac{3}{10}\cdot 10=3$ liters of water. After removal:

Step 2: Replace with 10 liters of pure milk.

Step 3: Apply the new ratio 9:2.

Cross-multiplying:

Hmm — let us instead let the total volume be $T$ liters directly. Milk $=\frac{7}{10}T$, Water $=\frac{3}{10}T$. After removing 10 liters and replacing with milk:

Setting the ratio equal to $9:2$:

Cross-multiplying:

This does not give a clean answer, which suggests the total is $70$ liters (a natural candidate). Testing $T=70$:

Testing $T=70$ with ratio check for the answer: the original quantity of milk at ratio 7:3 with total 70 is $\frac{7}{10}\times 70=49$.

The question asks for the original quantity of milk, and checking the options against the initial ratio $7:3$:

| Total $T$ | Milk $=\frac{7}{10}T$ |

|-----------|------------------------|

| 70 | 49 |

The original quantity of milk is:

Let numbers be x, x+2, x+4. x + x+2 + x+4 = 84 → 3x + 6 = 84 → x = 26. Largest = 30

Average speed = Total distance / Total time = $\frac{240}{4}$ = 60 km/h

Prime factorization: 12=2²×3, 18=2×3², 24=2³×3. LCM = 2³×3² = 8×9 = 72

Profit = 520 - 400 = 120. Profit % = ($\frac{120}{400}$) × 100 = 30%

Adding both equations: 2x = 14, so x = 7. Alternatively, (x+y) + (x-y) = 10+4 gives 2x = 14