SSC CGL / CHSL / MTS - MCQ Practice Questions

SI = (5000 × 10 × 2)/100 = 1000. CI = 5000(1.1)² - 5000 = 5000(1.21 - 1) = 1050. Difference = 1050 - 1000 = 50.

a:b = 3:4 means a/b = $\frac{3}{4}$. b:c = 5:6 means b/c = $\frac{5}{6}$. a/c = (a/b) × (b/c) = ($\frac{3}{4}$) × ($\frac{5}{6}$) = $\frac{15}{24}$. So a:c = 15:24.

Using Pythagorean theorem: distance = √(10² + 15²) = √(100 + 225) = √325 km ≈ 18.03 km.

Using formula: LCM × GCD = Product of numbers. 120 × 10 = 40 × x. 1200 = 40x. x = 30.

Let number = x. 0.4x = 96. x = 240. 65% of 240 = 0.65 × 240 = 156.

Rate of A+B = $\frac{1}{8}$. Rate of A = $\frac{1}{12}$. Rate of B = $\frac{1}{8}$ - $\frac{1}{12}$ = $\frac{3}{24}$ - $\frac{2}{24}$ = $\frac{1}{24}$. B takes 24 days.

Let CP = 100. MP = 150. SP = 150 × 0.8 = 120. Profit = 120 - 100 = 20. Profit% = 20%.

(x + 1/x)² = x² + 2 + 1/x² = 25. Therefore, x² + 1/x² = 25 - 2 = 23.

Original speed = $\frac{240}{4}$ = 60 km/h. New speed = 60 × 1.25 = 75 km/h. Time = $\frac{240}{75}$ = 3.2 hours = 3 hours 12 minutes

Let CP = x. Then 15x = 12 × SP, so SP = 1.25x. Profit% = (SP - CP)/CP × 100 = (1.25x - x)/x × 100 = 25%

Let numbers be 2x, 3x, 5x. Sum = 2x + 3x + 5x = 10x = 150. So x = 15. Largest number = 5x = 75

Work rate of person A = $\frac{1}{12}$ per day, person B = $\frac{1}{18}$ per day. Combined rate = $\frac{1}{12}$ + $\frac{1}{18}$ = $\frac{5}{36}$ per day. Work by A alone in 5 days = $\frac{5}{12}$. Remaining work = 1 - $\frac{5}{12}$ = $\frac{7}{12}$. Days together = ($\frac{7}{12}$)/($\frac{5}{36}$) = ($\frac{7}{12}$) × ($\frac{36}{5}$) = 4.2 ≈ 4 days