Quantitative Aptitude - MCQ Practice Questions

Step 1: Calculate the original speed

The train travels 240 km in 4 hours, so we divide distance by time.

Step 2: Calculate the new speed after 20% increase

The speed increases by 20%, so we multiply the original speed by 1.20.

Step 3: Calculate distance covered in 5 hours at new speed

Distance equals speed multiplied by time.

The train will cover 360 km in 5 hours at the new speed.

Step 1: Calculate Total Cost Price

The shopkeeper buys 120 notebooks at ₹40 each.

Step 2: Calculate Total Selling Price

The shopkeeper sells 120 notebooks at ₹50 each.

Step 3: Calculate Total Profit

Profit is the difference between selling price and cost price.

The shopkeeper's total profit for selling 120 notebooks in a day is ₹1,200.

Step 1: Identify the Simple Interest Formula

The formula for amount in simple interest is A = P + SI, where SI = PRT/100

Step 2: Substitute Known Values

Given: A = ₹9,600, T = 5 years, R = 8% per annum

Step 3: Simplify and Solve for Principal

The principal amount was ₹6,000.

Step 1: Identify the given values

Principal (P) = ₹5,000, Rate (R) = 6% per annum, Final Amount (A) = ₹6,500

Step 2: Calculate the Simple Interest

Simple Interest (SI) = Final Amount - Principal

Step 3: Apply the Simple Interest formula to find Time

Using the formula: $SI=\frac{P\times R\times T}{100}$

The amount will become ₹6,500 after 5 years.

Step 1: Identify Cost Price and Selling Price

Cost Price (CP) = ₹8 per kg and Selling Price (SP) = ₹12 per kg

Step 2: Calculate Profit

Profit = Selling Price − Cost Price

Step 3: Calculate Profit Percentage

Profit percentage is calculated as profit divided by cost price, multiplied by 100

The trader's profit percentage is 50%.

Step 1: Identify the given information

Cost Price (CP) = ₹450 and Loss = 8%

Step 2: Calculate the loss amount

Loss amount = 8% of Cost Price

Step 3: Calculate the selling price

Selling Price = Cost Price − Loss amount

The selling price of the article is ₹414.

Step 1: Find profit per notebook

The retailer buys at ₹40 and sells at ₹50, so profit on each notebook is the difference.

Step 2: Set up equation for total profit

Let the number of notebooks sold be x. The total profit equals profit per notebook multiplied by number of notebooks.

Step 3: Solve for number of notebooks

Divide both sides by 10 to find x.

The retailer must sell 60 notebooks to make a profit of ₹600.

Step 1: Use SI formula: SI = (P × R × T) / 100.

Step 2: SI = (5000 × 8 × 3) / 100 = $\frac{120000}{100}$ = ₹1,200.

Step 3: Total Amount = Principal + SI = 5000 + 1200 = ₹6,200.

So option A is correct.

Step 1: Find SI = Amount - Principal = 9600 - 8000 = ₹1,600.

Step 2: Use SI = (P × R × T) / 100, so 1600 = (8000 × R × 2) / 100.

Step 3: 1600 = 160R, therefore R = 10%.

So option B is correct.

Step 1: Find SI = 15600 - 12000 = ₹3,600.

Step 2: Use SI = (P × R × T) / 100, so 3600 = (12000 × 6 × T) / 100.

Step 3: 3600 = 720T, therefore T = 5 years.

So option B is correct.

Step 1: Use SI formula: SI = (P × R × T) / 100.

Step 2: SI = (10000 × 5 × 2.5) / 100 = $\frac{125000}{100}$ = ₹1,250.

Step 3: The interest earned is ₹1,250.

So option B is correct.

Step 1: Use formula A = P(1 + r/100)^n.

Step 2: A = 5000(1 + $\frac{8}{100}$)^2 = 5000(1.08)^2 = 5000 × 1.1664 = 5832.

Step 3: CI = A - P = 5832 - 5000 = ₹832.

So option A is correct.

Step 1: Use A = P(1 + r/100)^n.

Step 2: 9261 = 8000(1 + r/100)^3.

Step 3: (1 + r/100)^3 = $\frac{9261}{8000}$ = 1.157625.

Step 4: Taking cube root, 1 + r/100 = 1.05, so r = 5%.

So option B is correct.

Step 1: Use A = P(1 + r/100)^n formula.

Step 2: 13310 = 10000(1 + $\frac{10}{100}$)^n = 10000(1.1)^n.

Step 3: 1.331 = (1.1)^n.

Step 4: Taking log or testing: (1.1)^3 = 1.331.

Therefore n = 3 years.

So option C is correct.

Step 1: Profit = Selling Price - Cost Price = 520 - 400 = ₹120.

Step 2: Profit% = (Profit/CP) × 100 = ($\frac{120}{400}$) × 100 = 30%.

So option B is correct.

Step 1: Loss = 12% of CP = 0.12 × 1,500 = ₹180.

Step 2: SP = CP - Loss = 1,500 - 180 = ₹1,320.

So option B is correct.

Step 1: Let CP = x. SP = CP + Profit = x + 0.35x = 1.35x.

Step 2: 1.35x = 810, so x = $\frac{810}{1}$.35 = ₹600.

So option A is correct.

Step 1: Total Cost Price = 50 × 40 = ₹2,000.

Step 2: Total Selling Price = 50 × 48 = ₹2,400.

Step 3: Total Profit = 2,400 - 2,000 = ₹400.

So option C is correct.

Step 1: Cost Price (CP) = ₹450 per meter.

Step 2: Selling Price (SP) = ₹540 per meter.

Step 3: Profit = SP - CP = 540 - 450 = ₹90.

Step 4: Profit% = (Profit/CP) × 100 = ($\frac{90}{450}$) × 100 = 20%.

So option B is correct.

Step 1: Cost Price = ₹640.

Step 2: Loss = 8% of 640 = 0.08 × 640 = ₹51.20.

Step 3: Selling Price = CP - Loss = 640 - 51.20 = ₹588.80.

So option B is correct.