Quantitative Aptitude - MCQ Practice Questions

Total cost for A = 500 × 24 = ₹12,000. Total cost for B = 600 × 18 = ₹10,800. B costs less, so B is more cost-effective.

Downstream speed = $\frac{60}{3}$ = 20 km/h. Upstream speed = $\frac{60}{4}$ = 15 km/h. Speed of boat = (20+15)/2 = $\frac{35}{2}$ = 17.5 km/h.

SI = (P × R × T)/100 = (10000 × 10 × 3)/100 = 3000. Amount = 10000 + 3000 = ₹13,000.

Total distance = train length + platform length = 200 + 400 = 600m. Speed = $\frac{600}{30}$ = 20 m/s.

Profit = 1000 - 800 = ₹200. Profit% = ($\frac{200}{800}$) × 100 = 25%.

Let original number = x. x × 1.12 = 224. x = $\frac{224}{1}$.12 = 200.

Total distance = 4×2 + 5×3 = 8 + 15 = 23 km. Total time = 5 hours. Average speed = $\frac{23}{5}$ = 4.6 km/h. Option C is correct, not A.

A's work per day = $\frac{1}{12}$, B's work per day = $\frac{1}{18}$. Combined = $\frac{1}{12}$ + $\frac{1}{18}$ = $\frac{5}{36}$. Time = $\frac{36}{5}$ = 7.2 days

Fill rate = $\frac{1}{20}$, Empty rate = $\frac{1}{30}$. Net rate = $\frac{1}{20}$ - $\frac{1}{30}$ = $\frac{1}{60}$. Time = 60 hours

Total work = 24 × 16 = 384 worker-days. For 12 days: $\frac{384}{12}$ = 32 workers

A: SP = 500 × 1.20 = ₹600, Profit = ₹100. B: SP = 400 × 1.25 = ₹500, Profit = ₹100. Total profit = 200 on 900 = 22.22% (approx 22.73% for combined weighted avg)

Speed = $\frac{360}{6}$ = 60 km/h = 60 × $\frac{5}{18}$ = 16.67 m/s

SP = 1000 × (1 - 0.20) = 1000 × 0.80 = ₹800

Downstream speed = $\frac{48}{3}$ = 16 km/h, Upstream speed = $\frac{32}{4}$ = 8 km/h. Boat speed = (16+8)/2 = 12 km/h

SI = (P × R × T)/100 = (5000 × 8 × 2)/100 = ₹800

SP = CP × 1.20. 480 = CP × 1.20. CP = $\frac{480}{1}$.20 = ₹400

Fill rate = $\frac{1}{10}$, Empty rate = $\frac{1}{15}$. Net = $\frac{1}{10}$ - $\frac{1}{15}$ = $\frac{1}{30}$. Time = 30 hours

Let original price = 100. After 15% increase: 115. After 15% decrease: 115 × 0.85 = 97.75. Change = 97.75 - 100 = -2.25. Percentage change = -2.25%.

To find the total salary, we need to determine what percentage is saved, then use it to calculate the full amount.

Step 1: Find the percentage spent

The man spends money on food and rent:

Step 2: Find the percentage saved

Since total salary = 100%, the remaining amount is saved:

Step 3: Set up the equation

If 30% of his salary equals ₹3000:

Step 4: Solve for total salary

Verification: 40% of ₹10,000 = ₹4,000 (food); 30% of ₹10,000 = ₹3,000 (rent); Remaining = ₹10,000 − ₹7,000 = ₹3,000 ✓

**Answer: The total monthly salary is $₹10,000$ (Option A)**

Let original price = 100. After 20% increase: 120. After 10% increase: 120 × 1.10 = 132. Total increase = 32%.