Quantitative Aptitude - MCQ Practice Questions

Step 1: Selling Price = ₹18,900 and Profit = 35%.

Step 2: CP = SP / (1 + Profit%/100) = 18,$\frac{900}{1}$.35 = ₹14,000.

Step 3: Verification: Profit = 14,000 × 0.35 = ₹4,900; SP = 14,000 + 4,900 = ₹18,900 ✓.

So option B is correct.

Step 1: Selling Price = ₹56 per kg and Profit = 40%.

Step 2: CP = SP / (1 + Profit%/100) = $\frac{56}{1}$.40 = ₹40 per kg.

Step 3: Verification: Profit = 40 × 0.40 = ₹16; SP = 40 + 16 = ₹56 ✓.

So option C is correct.

Step 1: Cost Price (CP) = ₹240, Selling Price (SP) = ₹288.

Step 2: Profit = SP - CP = 288 - 240 = ₹48.

Step 3: Profit% = (Profit/CP) × 100 = ($\frac{48}{240}$) × 100 = 20%.

So option B is correct.

Step 1: Loss = 12%, so SP = 88% of CP.

Step 2: Let CP = x, then 0.88x = 1650.

Step 3: x = $\frac{1650}{0}$.88 = ₹1,875.

So option A is correct.

Step 1: SP = ₹12, Profit = 50%, so CP = $\frac{12}{1}$.50 = ₹8 per pen.

Step 2: Cost for 180 pens = 8 × 180 = ₹1,440.

So option A is correct.

Step 1: Interest = 2,928 - 2,400 = ₹528.

Step 2: Using SI = (P × R × T) / 100, we get 528 = (2,400 × R × 2) / 100.

Step 3: 528 = 48R, so R = 11% p.a.

Option B is correct.

Step 1: Interest = 4,392 - 3,600 = ₹792.

Step 2: Using SI = (P × R × T) / 100, we get 792 = (3,600 × 11 × T) / 100.

Step 3: 792 = 396T, so T = 2 years.

Option A is correct.

Using SI = (P × R × T) / 100, we have 3,600 = (8,000 × 15 × T) / 100.

Step 1: 3,600 = 1,200T.

Step 2: T = 3,$\frac{600}{1}$,200 = 3 years.

Option C is correct.

Step 1: Use compound interest formula A = P(1 + r/100)^n.

Step 2: A = 12000(1 + $\frac{8}{100}$)^2 = 12000(1.08)^2 = 12000 × 1.1664 = 13,996.80.

Step 3: The amount after 2 years is ₹13,996.80.

Step 1: Use formula 2P = P(1.10)^n where 2P is the doubled amount.

Step 2: Divide by P to get 2 = (1.10)^n.

Step 3: Taking log: n = log(2)/log(1.10) = 0.$\frac{301}{0}$.0414 ≈ 7.2 years.

Step 1: Discount = 15% of ₹800 = 0.15 × 800 = ₹120.

Step 2: Selling Price = Marked Price - Discount = 800 - 120 = ₹680.

Therefore, option A is correct.

Step 1: Increase in price = ₹50 - ₹40 = ₹10.

Step 2: Percentage increase = (Increase/Original Price) × 100 = ($\frac{10}{40}$) × 100 = 25%.

Therefore, option C is correct.

Step 1: Percentage = (Marks obtained/Total marks) × 100 = ($\frac{72}{120}$) × 100.

Step 2: = 0.6 × 100 = 60%.

Therefore, option B is correct.

Step 1: Profit = 20% of ₹250 = 0.20 × 250 = ₹50.

Step 2: Selling Price = Cost Price + Profit = 250 + 50 = ₹300.

Therefore, option B is correct.

Step 1: Population increase = 8% of 50,000 = 0.08 × 50,000 = 4,000.

Step 2: Current population = 50,000 + 4,000 = 54,000.

Therefore, option B is correct.

Step 1: Reduction in production = 18% of 5,000 = 0.18 × 5,000 = 900 units.

Step 2: Current production = 5,000 - 900 = 4,100 units per day.

Therefore, option C is correct.

Step 1: Profit = Selling Price - Cost Price = 312 - 240 = ₹72.

Step 2: Profit% = (Profit/CP) × 100 = ($\frac{72}{240}$) × 100 = 30%.

So option B is correct.

Step 1: Loss = 15% of CP = 15% of 500 = ₹75.

Step 2: Selling Price = CP - Loss = 500 - 75 = ₹425 per kg.

So option B is correct.

Step 1: Use SI formula = (P × R × T) / 100.

Step 2: SI = (8000 × 6 × 3) / 100 = $\frac{144000}{100}$ = ₹1440.

Step 3: Total Amount = Principal + SI = 8000 + 1440 = ₹9440.

Step 1: SI = Amount - Principal = 6500 - 5000 = ₹1500.

Step 2: Use SI = (P × R × T) / 100, so 1500 = (5000 × R × 5) / 100.

Step 3: 1500 = 250R, therefore R = $\frac{1500}{250}$ = 6% per annum.