Quantitative Aptitude - MCQ Practice Questions

Step 1: Use SI formula: SI = (P × R × T) / 100.

Step 2: SI = (5000 × 8 × 3) / 100 = $\frac{120000}{100}$ = ₹1,200.

Step 3: Total Amount = Principal + SI = 5000 + 1200 = ₹6,200.

So option A is correct.

Step 1: Find SI = Amount - Principal = 9600 - 8000 = ₹1,600.

Step 2: Use SI = (P × R × T) / 100, so 1600 = (8000 × R × 2) / 100.

Step 3: 1600 = 160R, therefore R = 10%.

So option B is correct.

Step 1: Find SI = 15600 - 12000 = ₹3,600.

Step 2: Use SI = (P × R × T) / 100, so 3600 = (12000 × 6 × T) / 100.

Step 3: 3600 = 720T, therefore T = 5 years.

So option B is correct.

Step 1: Use SI formula: SI = (P × R × T) / 100.

Step 2: SI = (10000 × 5 × 2.5) / 100 = $\frac{125000}{100}$ = ₹1,250.

Step 3: The interest earned is ₹1,250.

So option B is correct.

Step 1: Interest = 2,928 - 2,400 = ₹528.

Step 2: Using SI = (P × R × T) / 100, we get 528 = (2,400 × R × 2) / 100.

Step 3: 528 = 48R, so R = 11% p.a.

Option B is correct.

Step 1: Interest = 4,392 - 3,600 = ₹792.

Step 2: Using SI = (P × R × T) / 100, we get 792 = (3,600 × 11 × T) / 100.

Step 3: 792 = 396T, so T = 2 years.

Option A is correct.

Using SI = (P × R × T) / 100, we have 3,600 = (8,000 × 15 × T) / 100.

Step 1: 3,600 = 1,200T.

Step 2: T = 3,$\frac{600}{1}$,200 = 3 years.

Option C is correct.

Step 1: Use SI formula = (P × R × T) / 100.

Step 2: SI = (8000 × 6 × 3) / 100 = $\frac{144000}{100}$ = ₹1440.

Step 3: Total Amount = Principal + SI = 8000 + 1440 = ₹9440.

Step 1: SI = Amount - Principal = 6500 - 5000 = ₹1500.

Step 2: Use SI = (P × R × T) / 100, so 1500 = (5000 × R × 5) / 100.

Step 3: 1500 = 250R, therefore R = $\frac{1500}{250}$ = 6% per annum.

Step 1: We need SI = P, so SI = ₹12000.

Step 2: Using SI = (P × R × T) / 100, we get 12000 = (12000 × 8 × T) / 100.

Step 3: 12000 = 960T, therefore T = $\frac{12000}{960}$ = 12.5 years.

Step 1: From first investment, 2800 = (P × 14 × 5) / 100 = 0.7P.

Step 2: P = $\frac{2800}{0}$.7 = ₹4000.

Step 3: At 10% for 5 years, SI = (4000 × 10 × 5) / 100 = $\frac{200000}{100}$ = ₹2000.

SI for 2 years = 6000 - 5500 = 500. SI per year = 250. SI for 3 years = 750. Principal = 5500 - 750 = 4000

SI = 8640 - 7200 = 1440. Using SI = (P × R × T)/100; 1440 = (7200 × R × 2)/100; R = 10%

SI = 11700 - 9000 = 2700. Using T = (SI × 100)/(P × R) = (2700 × 100)/(9000 × 15) = 2 years

SI = (24000 × 8.5 × 4)/100 = 8160

If amount = 2P, then SI = P. Using P = (P × R × 10)/100; 100 = 10R; R = 10% p.a.

SI = (5000 × 12 × 2.5)/100 = 1500. Amount = 5000 + 1500 = 6500

SI = (20000 × 8 × 5)/100 = 8000. Amount = 20000 + 8000 = 28000

Using SI = (P × R × T)/100; 800 = (4000 × R × 2)/100; R = 10% p.a.