Quantitative Aptitude - MCQ Practice Questions

Relative speed = 40 + 50 = 90 km/h. Distance = 90 × 2 = 180 km

Amount = 10000(1.10)² = 10000 × 1.21 = ₹12100. CI = 12100 - 10000 = ₹2100

When multiple workers complete a task at different rates, their combined work rate equals the sum of individual rates. The combined rate is found by adding the reciprocals of individual completion times.

Step 1: Find individual work rates

Work rate is the fraction of work completed per day. If A completes work in 8 days, B in 12 days, and C in 16 days:

Step 2: Find combined work rate

When working together, rates add:

Step 3: Find common denominator and add

The LCM of 8, 12, and 16 is 48:

Step 4: Calculate time to complete work

If combined rate is $\frac{13}{48}$ per day, then time to complete 1 full work is:

**Answer: They can complete the work together in $\frac{48}{13}$ days or approximately 3.69 days (Option D)**

Monthly savings = 50000 × (1-0.60) = ₹20,000. Annual = 20,000 × 12 = ₹240,000

New income = Original × 1.25. 62,500 = Original × 1.25. Original = 62,$\frac{500}{1}$.25 = ₹50,000

Total distance = 200 + 100 = 300 m. Speed = 54 km/h = 15 m/s. Time = $\frac{300}{15}$ = 20 seconds

Total distance = 5×3 + 4×2 = 15 + 8 = 23 km. Total time = 5 hours. Avg speed = $\frac{23}{5}$ = 4.6 km/h

After 20% discount = 1000 × 0.80 = ₹800. After 10% discount = 800 × 0.90 = ₹720

Let A, B, C complete work in a, b, c days respectively. 1/a + 1/b = $\frac{1}{12}$, 1/b + 1/c = $\frac{1}{15}$, 1/a + 1/c = $\frac{1}{20}$. Adding all three: 2(1/a + 1/b + 1/c) = $\frac{1}{12}$ + $\frac{1}{15}$ + $\frac{1}{20}$ = $\frac{12}{60}$ = $\frac{1}{5}$. So 1/a + 1/b + 1/c = $\frac{1}{10}$. Therefore, 1/a = $\frac{1}{10}$ - $\frac{1}{15}$ = $\frac{1}{30}$. A completes work in 30 days.

Let CP of 1 article = 1. CP of 8 = 8. SP of 10 = 8, so SP of 1 = 0.8. Loss = 1 - 0.8 = 0.2 = 20%.

Let number = 100. After 50% increase: 150. After 50% decrease: 150 × 0.5 = 75. Net change = (75-100)/100 × 100 = -25%.

SP = CP × (1 + profit%) = 800 × 1.35 = 1080.

SI = (P × R × T)/100 = (5000 × 8 × 3)/100 = 1200. Total = 5000 + 1200 = 6200.

Value after 2024 = 10 × 1.12 = 11.2 lakhs. Value after 2025 = 11.2 × 1.08 = 12.096 ≈ 12.09 lakhs.

Equivalent discount = 100 - (90 × 80)/100 = 100 - 72 = 28%.

MP = 8000 × 1.60 = 12,800. SP = 12,800 × 0.75 = 9,600. Profit = 9,600 - 8,000 = 1,600. Profit% = (1,$\frac{600}{8}$,000) × 100 = 20%.

CP = 100, MP = 160, SP = 160 × 0.8 = 128. Profit% = 28%.

After 15% discount: 2000 × 0.85 = 1700. After 10% discount: 1700 × 0.9 = 1530.

When a man sells an item at a loss, the selling price is calculated as a percentage reduction from the cost price. Here, we lose 15% of the original value.

Step 1: Identify the given information

Cost Price (C.P.) = ₹1200

Loss percentage = 15%

Step 2: Calculate the loss amount

Loss amount is 15% of the cost price:

Step 3: Calculate the selling price

Selling price is obtained by subtracting the loss from the cost price:

Alternative method (direct formula):

When there is a loss of 15%, the selling price is 85% of the cost price:

Answer: The selling price is ₹1020 (Option D)

Value = 10,000 × (1.08)² = 10,000 × 1.1664 = 11,664.