Quantitative Aptitude - MCQ Practice Questions

Step 1: Calculate the Selling Price after discount

The marked price is ₹500 and discount is 20%.

Step 2: Use the profit formula to find Cost Price

The shopkeeper makes a profit of 25%, which means Selling Price is 125% of Cost Price.

Step 3: Solve for Cost Price

The cost price of the article is ₹320.

Step 1: SP at 20% loss = ₹1200, so CP = $\frac{1200}{0}$.80 = ₹1500.

Step 2: For 20% profit: New SP = CP × (1 + $\frac{20}{100}$) = 1500 × 1.20 = ₹1800.

So option B is correct.

Step 1: Let CP of 1 pen = ₹1.

Then CP of 12 pens = ₹12.

Step 2: SP of 10 pens = ₹12, so SP of 1 pen = ₹1.20.

Step 3: Profit% = [(1.20 - 1)/1] × 100 = 20%.

So option B is correct.

1. Calculate Total Cost Price (CP):The shopkeeper bought $100\text{ kg}$ of sugar at $₹20$ per kg.

2. Calculate Total Selling Price (SP):The shopkeeper sold the sugar in two batches:First batch: $60\text{ kg}$ at $₹25$ per kg.

Second batch: $40\text{ kg}$ at $₹18$ per kg.

3. Calculate Profit or Loss:Since the Total SP ($₹2220$) is greater than the Total CP ($₹2000$), the shopkeeper made a profit.

The shopkeeper made an overall profit of $₹220$.

Step 1: Let marked price = MP.

After 12% discount, SP = 0.88 × MP.

Step 2: 0.88 × MP = 275, so MP = $\frac{275}{0}$.88 = ₹312.50.

So option B is correct.

Step 1: Marked Price = 5,000 + 40% of 5,000 = 5,000 × 1.40 = ₹7,000.

Step 2: Selling Price = 7,000 - 15% of 7,000 = 7,000 × 0.85 = ₹5,950.

Step 3: Profit% = (5,950 - 5,000)/5,000 × 100 = $\frac{950}{5}$,000 × 100 = 19%.

So option B is correct.

Step 1: Let SP of each article = ₹100.

For first: CP₁ = $\frac{100}{1}$.25 = ₹80.

For second: CP₂ = $\frac{100}{0}$.75 = ₹133.33.

Step 2: Total CP = 80 + 133.33 = ₹213.33, Total SP = 200.

Step 3: Loss% = (213.33 - 200)/213.33 × 100 = 6.25%.

So option A is correct.

Step 1: Cost Price per lemon = $\frac{1}{5}$ = ₹0.20.

Selling Price per lemon = $\frac{1}{4}$ = ₹0.25.

Step 2: Profit per lemon = 0.25 - 0.20 = ₹0.05.

Step 3: Profit% = (0.$\frac{05}{0}$.20) × 100 = 25%.

So option B is correct.

Step 1: Let CP = ₹100.

Step 2: Marked Price (MP) = 100 + 35% of 100 = ₹135.

Step 3: Discount = 15% of 135 = ₹20.25.

Step 4: Selling Price = 135 - 20.25 = ₹114.75.

Step 5: Profit% = (114.75 - 100)/100 × 100 = 14.75%.

So option A is correct.

Step 1: Cost Price per dozen = ₹30, so CP per banana = $\frac{30}{12}$ = ₹2.50.

Step 2: Selling Price per banana = ₹3.60.

Step 3: Profit per banana = 3.60 - 2.50 = ₹1.10.

Step 4: Profit% = (1.$\frac{10}{2}$.50) × 100 = 44%.

So option C is correct.

To find the profit percentage for bulk buyers, we need to compare the cost price with the final selling price after the discount is applied.

Step 1: Identify the given values

Step 2: Calculate the selling price after discount

Step 3: Calculate profit

Step 4: Calculate profit percentage

Cost price (CP) per egg = ₹2.40

Marked price (MP) per egg = ₹3.60

Discount = 20%

Selling price (SP) after discount:

SP=3.60×(1−

100

20

​

)

=3.60×0.8

=₹2.88

Profit per egg:

2.88−2.40=₹0.48

Profit percentage:

2.40

0.48

​

×100

=20%

Therefore, the profit percentage for bulk buyers is 20%.

**Answer: The profit percentage for bulk buyers is $20\%$ (Option B)**

Step 1: CP = ₹450.

Marked Price = 450 × 1.60 = ₹720.

Step 2: SP after 10% discount = 720 × 0.90 = ₹648.

Step 3: Profit% = [(648 - 450)/450] × 100 = ($\frac{198}{450}$) × 100 = 44%.

So option B is correct.

Step 1: For first article with 20% profit: SP = ₹960, so CP₁ = $\frac{960}{1}$.20 = ₹800.

Step 2: For second article with 20% loss: SP = ₹960, so CP₂ = $\frac{960}{0}$.80 = ₹1,200.

Step 3: Total CP = 2,000, Total SP = 1,920.

Loss% = ($\frac{80}{2000}$) × 100 = 4%.

So option C is correct.

Step 1: Marked Price = ₹800, Discount = 12% of 800 = ₹96.

Step 2: Selling Price = 800 - 96 = ₹704.

Step 3: Profit = 704 - 600 = ₹104.

Step 4: Profit% = ($\frac{104}{600}$) × 100 = 17.33% ≈ 16%.

So option C is correct.

Step 1: Total CP = 50 × 40 = ₹2000.

Step 2: 80% of 50 = 40 kg sold at ₹50/kg = ₹2000, remaining 10 kg at ₹35/kg = ₹350.

Step 3: Total SP = 2000 + 350 = ₹2350.

Step 4: Profit% = ($\frac{350}{2000}$) × 100 = 17.5% ≈ 20%.

So option C is correct.

Step 1: Item A: SP = 400 + (25% of 400) = 400 + 100 = ₹500.

Step 2: Item B: SP = 400 - (18% of 400) = 400 - 72 = ₹328.

Step 3: Total CP = 800, Total SP = 828.

Step 4: Profit% = ($\frac{28}{800}$) × 100 = 3.5%.

So option A is correct.

Step 1: CP = ₹5000.

Step 2: Marked Price = 5000 + (60% of 5000) = 5000 + 3000 = ₹8000.

Step 3: Discount = 20% of 8000 = ₹1600.

Step 4: SP = 8000 - 1600 = ₹6400.

Step 5: Profit% = ($\frac{1400}{5000}$) × 100 = 28%.

So option A is correct.

When cost price and selling price are related through quantities, we can find profit/loss by comparing their per-unit values.

Step 1: Set Up the Given Relationship

We're told that the cost price of 18 items equals the selling price of 15 items. Let's denote the cost price per item as CP and selling price per item as SP.

Step 2: Find the Ratio of Selling Price to Cost Price

Rearranging the equation to find the relationship between SP and CP:

Step 3: Calculate Profit Percentage

Since SP > CP, there is a profit. The profit percentage is calculated as:

The profit percentage is 20%, so the answer is (B) 20% profit.

Let manufacturer's CP = x. Wholesaler's CP = 1.2x. Retailer's CP = 1.2x × 1.25 = 1.5x. Customer pays = 1.5x × 1.3 = 1.95x = 1,950. So x = 1,000.

Article 1: CP₁ = $\frac{1200}{1}$.2 = ₹1,000. Article 2: CP₂ = $\frac{1200}{0}$.8 = ₹1,500. Total CP = ₹2,500, Total SP = ₹2,400. Loss = 4%.