Quantitative Aptitude - MCQ Practice Questions

To find the required selling price, we need to work backwards from the desired overall profit.

Step 1: Calculate Selling Price of Item A

Item A is sold at 15% profit on its cost price of ₹4,000.

Step 2: Calculate Total Cost Price and Required Total Selling Price

The total cost price of both items combined is the sum of individual cost prices.

For an overall profit of 5%, the total selling price should be:

Step 3: Find Required Selling Price of Item B

Since Total Selling Price = Selling Price of A + Selling Price of B:

The selling price of Item B should be ₹5,900.

Cost price of Item A =₹4,000

Sold at 15% profit:

SP

A

​

=4000+15% of 4000

=4000+600=₹4600

Cost price of Item B =₹6,000

Total cost price:

4000+6000=₹10,000

For an overall profit of 5%:

Required total selling price=10000+5% of 10000

=10000+500=₹10,500

Therefore, required selling price of Item B:

SP

B

​

=10500−4600

=₹5900

So, the selling price of Item B should be:

₹5,900

​

Answer: (B) 5900

Step 1: Identify Cost Price and Selling Price

Cost Price (CP) = ₹8 per kg and Selling Price (SP) = ₹12 per kg

Step 2: Calculate Profit

Profit = Selling Price − Cost Price

Step 3: Calculate Profit Percentage

Profit percentage is calculated as profit divided by cost price, multiplied by 100

The trader's profit percentage is 50%.

Step 1: Identify the given information

Cost Price (CP) = ₹450 and Loss = 8%

Step 2: Calculate the loss amount

Loss amount = 8% of Cost Price

Step 3: Calculate the selling price

Selling Price = Cost Price − Loss amount

The selling price of the article is ₹414.

Step 1: Calculate the Selling Price after discount

The marked price is ₹500 and discount is 20%.

Step 2: Use the profit formula to find Cost Price

The shopkeeper makes a profit of 25%, which means Selling Price is 125% of Cost Price.

Step 3: Solve for Cost Price

The cost price of the article is ₹320.

Step 1: Find the Cost Price of the first item (25% profit)

If selling price is ₹2,000 with 25% profit, then SP = CP × 1.25

Step 2: Find the Cost Price of the second item (25% loss)

If selling price is ₹2,000 with 25% loss, then SP = CP × 0.75

Step 3: Calculate overall profit or loss percentage

Total Cost Price = ₹1,600 + ₹2,666.67 = ₹4,266.67

Total Selling Price = ₹2,000 + ₹2,000 = ₹4,000

**The merchant made an overall loss of 6.

Step 1: Find profit per notebook

The retailer buys at ₹40 and sells at ₹50, so profit on each notebook is the difference.

Step 2: Set up equation for total profit

Let the number of notebooks sold be x. The total profit equals profit per notebook multiplied by number of notebooks.

Step 3: Solve for number of notebooks

Divide both sides by 10 to find x.

The retailer must sell 60 notebooks to make a profit of ₹600.

Step 1: SP at 20% loss = ₹1200, so CP = $\frac{1200}{0}$.80 = ₹1500.

Step 2: For 20% profit: New SP = CP × (1 + $\frac{20}{100}$) = 1500 × 1.20 = ₹1800.

So option B is correct.

Step 1: Marked Price = ₹1000.

Wholesaler's SP (Retailer's CP) = 1000 × (1 - 0.30) = ₹700.

Step 2: Retailer marks at 20% above CP: New MP = 700 × 1.20 = ₹840.

Step 3: Retailer gives 10% discount: Final SP = 840 × 0.90 = ₹756.

So option A is correct.

Step 1: Let CP of 1 pen = ₹1.

Then CP of 12 pens = ₹12.

Step 2: SP of 10 pens = ₹12, so SP of 1 pen = ₹1.20.

Step 3: Profit% = [(1.20 - 1)/1] × 100 = 20%.

So option B is correct.

1. Calculate Total Cost Price (CP):The shopkeeper bought $100\text{ kg}$ of sugar at $₹20$ per kg.

2. Calculate Total Selling Price (SP):The shopkeeper sold the sugar in two batches:First batch: $60\text{ kg}$ at $₹25$ per kg.

Second batch: $40\text{ kg}$ at $₹18$ per kg.

3. Calculate Profit or Loss:Since the Total SP ($₹2220$) is greater than the Total CP ($₹2000$), the shopkeeper made a profit.

The shopkeeper made an overall profit of $₹220$.

Step 1: Profit = Selling Price - Cost Price = 520 - 400 = ₹120.

Step 2: Profit% = (Profit/CP) × 100 = ($\frac{120}{400}$) × 100 = 30%.

So option B is correct.

Step 1: Loss = 12% of CP = 0.12 × 1,500 = ₹180.

Step 2: SP = CP - Loss = 1,500 - 180 = ₹1,320.

So option B is correct.

Step 1: Let CP = x. SP = CP + Profit = x + 0.35x = 1.35x.

Step 2: 1.35x = 810, so x = $\frac{810}{1}$.35 = ₹600.

So option A is correct.

Step 1: Total Cost Price = 50 × 40 = ₹2,000.

Step 2: Total Selling Price = 50 × 48 = ₹2,400.

Step 3: Total Profit = 2,400 - 2,000 = ₹400.

So option C is correct.

Step 1: Let marked price = MP.

After 12% discount, SP = 0.88 × MP.

Step 2: 0.88 × MP = 275, so MP = $\frac{275}{0}$.88 = ₹312.50.

So option B is correct.

Step 1: Marked Price = 5,000 + 40% of 5,000 = 5,000 × 1.40 = ₹7,000.

Step 2: Selling Price = 7,000 - 15% of 7,000 = 7,000 × 0.85 = ₹5,950.

Step 3: Profit% = (5,950 - 5,000)/5,000 × 100 = $\frac{950}{5}$,000 × 100 = 19%.

So option B is correct.

Step 1: Let SP of each article = ₹100.

For first: CP₁ = $\frac{100}{1}$.25 = ₹80.

For second: CP₂ = $\frac{100}{0}$.75 = ₹133.33.

Step 2: Total CP = 80 + 133.33 = ₹213.33, Total SP = 200.

Step 3: Loss% = (213.33 - 200)/213.33 × 100 = 6.25%.

So option A is correct.

Step 1: Cost Price per lemon = $\frac{1}{5}$ = ₹0.20.

Selling Price per lemon = $\frac{1}{4}$ = ₹0.25.

Step 2: Profit per lemon = 0.25 - 0.20 = ₹0.05.

Step 3: Profit% = (0.$\frac{05}{0}$.20) × 100 = 25%.

So option B is correct.

Step 1: SP of first laptop = 25,000 × 1.12 = ₹28,000.

Step 2: SP of second laptop = 25,000 × 0.84 = ₹21,000.

Step 3: Total SP = 28,000 + 21,000 = ₹49,000.

So option B should be correct, but rechecking: 25,000 × 0.84 = 21,000 and 25,000 × 1.12 = 28,000, total = 49,000.

Correction: option is ₹49,000.

Step 1: Cost Price (CP) = ₹450 per meter.

Step 2: Selling Price (SP) = ₹540 per meter.

Step 3: Profit = SP - CP = 540 - 450 = ₹90.

Step 4: Profit% = (Profit/CP) × 100 = ($\frac{90}{450}$) × 100 = 20%.

So option B is correct.