Quantitative Aptitude - MCQ Practice Questions

CP × 1.1 = 1100, so CP = 1000.

Value = 500,000 × (0.95)² = 500,000 × 0.9025 = 451,250.

2025 revenue = 1 crore × 1.35 = 1.35 crore.

Profit per mango = 5. Total profit = 5 × 100 = 500.

New price = 1.25P. For constant expenditure: New consumption = $\frac{1}{1}$.25 = 0.8. Reduction = 20%.

SI = (50,000 × 10 × T)/100. 15,000 = 5000T. T = 3 years.

CP = 100, MP = 180, SP = 144 (for 44% profit). Discount = 180 - 144 = 36. Discount% = ($\frac{36}{180}$) × 100 = 20%.

Initial price × 1.16 = 465. Initial price = $\frac{465}{1}$.16 = 400.

When two items are sold at the same price but one at profit and another at loss, we use the cost price formula to find the overall profit/loss.

Step 1: Find Cost Price of Item 1 (25% profit)

If selling price is ₹900 at 25% profit, then:

Step 2: Find Cost Price of Item 2 (25% loss)

If selling price is ₹900 at 25% loss, then:

Step 3: Calculate Total Cost Price and Total Selling Price

Step 4: Find Overall Profit/Loss

Selling price (SP) of each item = ₹900

First item: 25% profit

CP

1

​

=

125

900×100

​

=₹720

Second item: 25% loss

CP

2

​

=

75

900×100

​

=₹1200

Total Cost Price

720+1200=₹1920

Total Selling Price

900+900=₹1800

Loss

1920−1800=₹120

Loss Percentage

1920

120

​

×100=6.25%

Therefore, the overall result is a loss of 6.25%.

Answer: Overall loss is ₹120 (Option C) ₹120 loss

Let C = 100. B = 110. A = 1.2 × 110 = 132. A is 32% more than C.

40% of MP = 480. MP = $\frac{480}{0}$.4 = 1200.

Increase = 6000. Percentage = ($\frac{6000}{30000}$) × 100 = 20%.

SP = 2000 × 1.15 = 2300.

If SP = ₹450 and discount = 10%, then MP × 0.9 = 450. MP = $\frac{450}{0}$.9 = ₹500

Effective discount = 20 + 15 - (20×15)/100 = 35 - 3 = 32%

Let B's salary = x. A's salary = 1.4x. x + 1.4x = 84,000. 2.4x = 84,000. x = ₹35,000

Population after 2 years = 10,00,000 × (1.05)² = 10,00,000 × 1.1025 = 11,02,500

Profit% = [(42-30)/30] × 100 = ($\frac{12}{30}$) × 100 = 40%

This problem uses the relationship between price reduction, quantity purchased, and total expenditure. We'll set up an equation comparing purchases before and after the price change.

Step 1: Define variables

Let the original price of sugar be $P$ per kg.

After a 15% reduction, the new price is:

Step 2: Set up the quantity equation

With ₹510, the customer can buy:

The difference is 3 kg:

Step 3: Simplify the equation

Factor out 510:

Step 4: Solve for P

Verification: At ₹30/kg: buys $\frac{510}{30}=17$ kg. At ₹25.50/kg: buys $\frac{510}{25.50}=20$ kg. Difference = 3 kg. ✓

Answer: The original price was ₹30 per kg (Option A)

Net change = 20 - 10 - (20×10)/100 = 10 - 2 = 8% increase