Quantitative Aptitude - MCQ Practice Questions

To find how many additional days are needed, we use the relationship between work completed and time, where work rate remains constant.

Step 1: Find the daily work rate

If 30% of the job is completed in 6 days, the daily rate is:

Step 2: Calculate total days needed for 80% of the job

At a constant rate of 5% per day, the time to complete 80% is:

Step 3: Find additional days needed

The worker has already spent 6 days on the first 30%. Additional days required:

Answer: The worker needs 10 more days to complete 80% of the job (Option A)

A's rate = $\frac{1}{12}$, B's rate = $\frac{1}{15}$. Combined = $\frac{1}{12}$ + $\frac{1}{15}$ = $\frac{9}{60}$ = $\frac{3}{20}$. In 3 min = 3 × $\frac{3}{20}$ = $\frac{9}{20}$ filled. Remaining = $\frac{11}{20}$. Only A works = ($\frac{11}{20}$)/($\frac{1}{12}$) = ($\frac{11}{20}$) × 12 = 6.6 ≈ 5 minutes (approx)

Total distance = (60 × 2) + (80 × 3) = 120 + 240 = 360 km. Total time = 5 hours. Average speed = $\frac{360}{5}$ = 72 km/h

SI = (5000 × 8 × 3)/100 = 1,200. Total = 5,000 + 1,200 = ₹6,200

A = 10,000(1.10)² = 10,000 × 1.21 = ₹12,100. CI = 12,100 - 10,000 = ₹2,100

Milk = ($\frac{3}{5}$) × 60 = 36L, Water = 24L. For 1:1 ratio, milk = water, so need 36L water. Water to add = 36 - 24 = 12L

Total spent = 25% + 20% + 15% = 60%. Remaining = 40% = ₹8,000. Total income = 8,$\frac{000}{0}$.40 = ₹20,000

Let CP = 100, MP = 150. SP = 150 × 0.70 = 105. Profit = 5%. Profit% = 5%

x% of 480 = 72, so x = 15%. For 96: ($\frac{96}{480}$) × 100 = 20%

Increase = 2,500 - 2,000 = 500. Percentage = ($\frac{500}{2}$,000) × 100 = 25%

Let B = 100, A = 75. B is more than A by 25 on base of 75 = ($\frac{25}{75}$) × 100 = 33.33%