Placement Papers - MCQ Practice Questions

Series follows n(n+1): 1×2=2, 2×3=6, 3×4=12, 4×5=20, 5×6=30, 6×7=42

a:b = 3:4, b:c = 5:6. Multiply first by 5 and second by 4: a:b = 15:20, b:c = 20:24. So a:b:c = 15:20:24

Using set theory: n(M∪S) = n(M) + n(S) - n(M∩S). 50 = 30 + 25 - n(M∩S). n(M∩S) = 5

(x + 1/x)² = x² + 2 + 1/x² = 7 + 2 = 9. So x + 1/x = ±3

After north and south movements (cancel out), he is only 3 km east of starting point

At 3:15, minute hand at 3 (90°), hour hand at 3 + $\frac{15}{60}$ × 30 = 97.5°. Difference = 7.5°

Since some doctors are teachers, and all teachers are educated, some doctors must be educated

R=6, O=9, S=1, E=8. So NOSE = 1-9-1-8 = 1918

Orange is a type of fruit. Shark is a type of fish. This is a classification relationship

First letter advances (A→B→C→D→E), second letter reverses (Z→Y→X→W→V)

PLUOITCMAC rearranged = COMPLIANT (meaning willing/agreeable)

Arrays allocate continuous memory blocks; linked lists use nodes scattered in memory

SaaS (Software as Service), PaaS (Platform as Service), IaaS (Infrastructure as Service) are main cloud models. DaaS is Data as Service but not standard

Quick sort has average time complexity O(n log n), better than bubble sort O(n²)

Encapsulation is bundling data (variables) and methods together while hiding implementation details

If no modifier is specified in Java, it defaults to package-private (accessible within the same package)

A compiler translates the entire program before execution (unlike interpreters which translate line by line)

MVC (Model View Controller) is an architectural pattern separating data, presentation, and logic

Each letter is shifted 3 positions forward in the alphabet (C→F, O→R, M→P, P→S, U→X, T→W, E→H, R→U). Applying the same to KEYBOARD: K→N, E→H, Y→B, B→E, O→R, A→D, R→U, D→G, wait—checking pattern: K(11)→N(14), E(5)→H(8), Y(25)→B(2), B(2)→E(5), O(15)→R(18), A(1)→D(4), R(18)→U(21), D(4)→G(7). KEYBOARD→NEYERMYNO confirms the +3 shift with wraparound.

Starting with x=5. ++x increments x to 6 and returns 6. x++ uses 6 and then increments x to 7. The third x uses 7. So y = 6 + 6 + 7 = 19. After the expression, x=8 (post-increment from x++ happens after the expression). Final: x=8, y=19.