Placement Papers - MCQ Practice Questions

Total distance = 120 + 150 = 270 km. Total time = 2 + 3 = 5 hours. Average speed = $\frac{270}{5}$ = 54 km/h

LCM of 12 and 18 = 36. Any number divisible by both 12 and 18 must be divisible by their LCM, which is 36

CI = P[(1 + r/100)^n - 1] = 10000[(1.1)^2 - 1] = 10000[0.21] = Rs. 2,100

Work = 5 × 12 = 60 worker-days. Days for 8 workers = $\frac{60}{8}$ = 7.5 days

Profit = 520 - 400 = 120. Profit% = ($\frac{120}{400}$) × 100 = 30%

Series follows n(n+1): 1×2=2, 2×3=6, 3×4=12, 4×5=20, 5×6=30, 6×7=42

a:b = 3:4, b:c = 5:6. Multiply first by 5 and second by 4: a:b = 15:20, b:c = 20:24. So a:b:c = 15:20:24

Using set theory: n(M∪S) = n(M) + n(S) - n(M∩S). 50 = 30 + 25 - n(M∩S). n(M∩S) = 5

(2.5)² - (1.5)² / 2 = [6.25 - 2.25] / 2 = $\frac{4}{2}$ = 2

(x + 1/x)² = x² + 2 + 1/x² = 7 + 2 = 9. So x + 1/x = ±3

144=12², 169=13², 196=14², but 195 is not a perfect square (√195 ≈ 13.96)

This is the Fibonacci sequence where each number is the sum of the previous two: 5+8=13

0.30 × x = 45. x = $\frac{45}{0}$.30 = 150

After north and south movements (cancel out), he is only 3 km east of starting point

At 3:15, minute hand at 3 (90°), hour hand at 3 + $\frac{15}{60}$ × 30 = 97.5°. Difference = 7.5°

This is deductive reasoning. If cats are animals and animals breathe, then cats must breathe

Since some doctors are teachers, and all teachers are educated, some doctors must be educated

R=6, O=9, S=1, E=8. So NOSE = 1-9-1-8 = 1918

Orange is a type of fruit. Shark is a type of fish. This is a classification relationship

First letter advances (A→B→C→D→E), second letter reverses (Z→Y→X→W→V)