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JEE Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

143 Q 5 Topics Take Test
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Difficulty: All Easy Medium Hard 91–100 of 143
Topics in JEE Chemistry
The oxidation of primary alcohols with chromic acid (H2CrO4) in acidic medium gives:
A Aldehydes
B Ketones
C Carboxylic acids
D Esters
Correct Answer:  C. Carboxylic acids
EXPLANATION

Chromic acid oxidizes primary alcohols to carboxylic acids. The aldehyde is an intermediate which is further oxidized.

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Which reagent is used to differentiate between aldehydes and ketones?
A Tollens reagent
B Fehling reagent
C Both A and B
D Bromine water
Correct Answer:  C. Both A and B
EXPLANATION

Both Tollens and Fehling reagents give positive test with aldehydes (silver mirror and red precipitate respectively) but not with ketones.

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Which of the following compounds undergoes SN1 reaction most readily?
A (CH3)3C-Br
B CH3-CH2-Br
C (CH3)2CH-Br
D CH3-Br
Correct Answer:  A. (CH3)3C-Br
EXPLANATION

Tertiary alkyl halides form stable tertiary carbocations, making SN1 mechanism favorable.

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In the Friedel-Crafts alkylation of benzene with alkyl halides, the catalyst used is:
A FeBr3
B AlCl3
C ZnCl2
D BF3
Correct Answer:  B. AlCl3
EXPLANATION

AlCl3 is the standard Lewis acid catalyst for Friedel-Crafts alkylation. It activates the alkyl halide to form a carbocation, which then attacks the aromatic ring.

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Grignard reagent (RMgX) reacts with water to give:
A R-OH and MgX2
B R-H and Mg(OH)X
C R-H and MgX2
D R-OMgX and H2
Correct Answer:  C. R-H and MgX2
EXPLANATION

Grignard reagents are strong nucleophiles and strong bases. They readily abstract a proton from water, producing an alkane (R-H) and magnesium halide salt.

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Which functional group shows a strong absorption around 1700-1750 cm⁻¹ in IR spectrum?
A Ether
B Alcohol
C Carbonyl
D Alkene
Correct Answer:  C. Carbonyl
EXPLANATION

The C=O stretch of carbonyl compounds (aldehydes, ketones, carboxylic acids, esters) appears characteristically around 1700-1750 cm⁻¹ in IR spectrum.

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In the nitration of benzene using HNO3/H2SO4, the electrophile is:
A NO3-
B NO2+
C HNO3
D H+
Correct Answer:  B. NO2+
EXPLANATION

H2SO4 protonates HNO3 to form H2NO3+, which loses water to generate the nitronium ion (NO2+), the actual electrophile in electrophilic aromatic substitution.

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The IUPAC name of the compound with structure CH3-CH(OH)-CH2-CHO is:
A 3-hydroxyhexanal
B 3-hydroxybutanal
C 2-hydroxybutanal
D 1-hydroxy-3-butanal
Correct Answer:  B. 3-hydroxybutanal
EXPLANATION

The longest carbon chain contains 4 carbons with the aldehyde group (CHO) at position 1. The hydroxyl group is at position 3, giving 3-hydroxybutanal.

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Which of the following compounds will undergo SN2 reaction most readily?
A tert-butyl chloride
B ethyl bromide
C neopentyl chloride
D isopropyl iodide
Correct Answer:  B. ethyl bromide
EXPLANATION

SN2 reaction requires easy access to the carbon bearing the leaving group. Ethyl bromide (primary alkyl halide) has minimal steric hindrance and is highly reactive in SN2 reactions.

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Q.100 Easy Organic Chemistry
In the polymer synthesis by condensation polymerization, the type of linkage formed when dicarboxylic acids react with diols is:
A Peptide bond
B Ester linkage
C Ether linkage
D Glycosidic bond
Correct Answer:  B. Ester linkage
EXPLANATION

When dicarboxylic acids (HOOC-R-COOH) react with diols (HO-R'-OH), ester bonds form between the carboxyl and hydroxyl groups, creating polyester polymers with repeating ester linkages.

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