Govt Exams
Total distance = train length + platform length = 200 + 400 = 600m. Speed = 600/30 = 20 m/s.
SI = (P × R × T)/100 = (10000 × 10 × 3)/100 = 3000. Amount = 10000 + 3000 = ₹13,000.
Downstream speed = 60/3 = 20 km/h. Upstream speed = 60/4 = 15 km/h. Speed of boat = (20+15)/2 = 35/2 = 17.5 km/h.
Total cost for A = 500 × 24 = ₹12,000. Total cost for B = 600 × 18 = ₹10,800. B costs less, so B is more cost-effective.
Let original number = 100. After 25% increase = 125. After 20% decrease of 125 = 125 × 0.8 = 100. Wait, let me recalculate: 125 × (100-20)/100 = 125 × 80/100 = 100. Net change = 0. Actually answer is D (No change). Let me verify: 1.25 × 0.8 = 1. So net is no change. Correction: The answer should be D.
Filling rate = 1/15 per hour. Emptying rate = 1/20 per hour. Net rate = 1/15 - 1/20 = (4-3)/60 = 1/60. Time = 60 hours.
Work done by A in 1 day = 1/20. Work done by A+B in 1 day = 1/12. So B's work in 1 day = 1/12 - 1/20 = (5-3)/60 = 2/60 = 1/30. Therefore B takes 30 days.
CP per banana = 30/12 = 2.5. SP per banana = 3. Profit = 0.5. Percentage = (0.5/2.5) × 100 = 20%
Let original = x. x × 1.15 = 299. x = 299/1.15 = 260
Fill rate = 1/20, Drain rate = 1/30. Net rate = 1/20 - 1/30 = 3/60 - 2/60 = 1/60. Time = 60 minutes