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JEE Chemistry
Chemical Kinetics

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

19 Q 5 Topics Take Test
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Difficulty: All Easy Medium Hard 1–10 of 19
Topics in JEE Chemistry
Which factor does NOT affect the rate constant k of a reaction?
A Temperature
B Concentration of reactants
C Nature of reactants
D Presence of catalyst
Correct Answer:  B. Concentration of reactants
EXPLANATION

Rate constant k is independent of reactant concentration; it depends on T, nature of reactants, and catalyst

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Consider the mechanism: (1) A + B ⇌ C (fast equilibrium), (2) C + D → E + F (slow). Which is the rate-determining step?
A Step 1
B Step 2
C Both steps
D Cannot be determined
Correct Answer:  B. Step 2
EXPLANATION

The slowest step in a mechanism is the rate-determining step (RDS), which is step 2

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For a zero-order reaction, the integrated rate law is [A] = [A]₀ - kt. If [A]₀ = 0.5 M and k = 0.02 M·s⁻¹, find time when [A] = 0
A 15 s
B 20 s
C 25 s
D 30 s
Correct Answer:  C. 25 s
EXPLANATION

0 = 0.5 - 0.02t; t = 0.5/0.02 = 25 s

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Which of the following statements about collision theory is INCORRECT?
A Molecules must collide with proper orientation
B All collisions lead to reaction
C Collision frequency increases with temperature
D Only collisions with energy ≥ Eₐ are effective
Correct Answer:  B. All collisions lead to reaction
EXPLANATION

Not all collisions are effective; only those with proper orientation and sufficient energy lead to reaction

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Half-life of a first-order reaction is 30 minutes. What fraction of reactant remains after 90 minutes?
A 1/2
B 1/4
C 1/8
D 1/16
Correct Answer:  C. 1/8
EXPLANATION

After 90 min = 3 half-lives, remaining = (1/2)³ = 1/8

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For the reaction 2NO + O₂ → 2NO₂, the rate law is Rate = k[NO]²[O₂]. What is the overall order of reaction?
A First order
B Second order
C Third order
D Zero order
Correct Answer:  C. Third order
EXPLANATION

Overall order = sum of exponents in rate law = 2 + 1 = 3 (third order)

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For an elementary reaction: A + A + B → Products, the rate law is:
A Rate = k[A][B]
B Rate = k[A]²[B]
C Rate = k[A][B]²
D Rate = k[A]³[B]
Correct Answer:  B. Rate = k[A]²[B]
EXPLANATION

For elementary reactions, the rate law is determined by the stoichiometry: Rate = k[A]²[B], as 2 A molecules and 1 B molecule participate

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For the reaction A → B, experimental data shows: [A] vs time is a straight line. This indicates:
A First-order reaction
B Zero-order reaction
C Second-order reaction
D Third-order reaction
Correct Answer:  B. Zero-order reaction
EXPLANATION

A straight line in [A] vs time plot indicates [A] = [A]₀ - kt, which is the integrated rate law for zero-order reactions

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For a reaction with rate law Rate = k[A]⁰[B]¹, if [B] is increased 4 times while [A] remains constant, the rate increases by:
A 2 times
B 4 times
C 8 times
D 16 times
Correct Answer:  B. 4 times
EXPLANATION

Since the reaction is first-order in B and zero-order in A, Rate ∝ [B]. Increasing [B] by 4 times increases Rate by 4 times

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A catalyst increases the rate of reaction by:
A Increasing activation energy
B Providing an alternative reaction pathway with lower activation energy
C Increasing the frequency factor
D Changing the equilibrium constant
Correct Answer:  B. Providing an alternative reaction pathway with lower activation energy
EXPLANATION

A catalyst works by providing an alternative mechanism with lower Ea, thus increasing reaction rate without being consumed

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