SSC CGL / CHSL / MTS
Combined Graduate Level — all sections
Showing 71–71 of 71 questions
A mixture contains 60% alcohol. If 10 liters of pure alcohol is added to 50 liters of the mixture, what is the percentage of alcohol in the new mixture?
Correct Answer:
C. 66.67%
EXPLANATION
Alcohol in original = 50 × 0.6 = 30 liters. New alcohol = 30 + 10 = 40. New total = 60. % = (40/60) × 100 = 66.67%