Home Subjects JEE Chemistry

JEE Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

225 Q 5 Topics Take Test
Advertisement
Difficulty: All Easy Medium Hard 131–140 of 225
Topics in JEE Chemistry
Q.131 Medium Organic Chemistry
The major product when 2-methylbut-3-en-1-ol undergoes PCC oxidation is:
A 2-methylbut-3-en-1-aldehyde
B 2-methylbut-3-enoic acid
C 2-methylbut-3-en-1-one
D 2-methylbutyric acid
Correct Answer:  A. 2-methylbut-3-en-1-aldehyde
EXPLANATION

PCC (Pyridinium chlorochromate) selectively oxidizes primary alcohols to aldehydes without further oxidation, and doesn't affect C=C.

Take Test
Q.132 Medium Organic Chemistry
In the Clemmensen reduction of a ketone, the reducing agent used is:
A Zn(Hg) and conc. HCl
B LiAlH4
C NaBH4
D H2 with Pd-C
Correct Answer:  A. Zn(Hg) and conc. HCl
EXPLANATION

Clemmensen reduction uses zinc amalgam with concentrated HCl to convert C=O to CH2, unlike Wolff-Kishner which uses hydrazine.

Take Test
Q.133 Medium Organic Chemistry
In the reaction of phenylmagnesium bromide (Grignard reagent) with CO2 followed by hydrolysis, the main product is:
A Benzene
B Benzoic acid
C Phenol
D Benzaldehyde
Correct Answer:  B. Benzoic acid
EXPLANATION

Grignard reagent attacks CO2 to form a salt, which upon hydrolysis gives benzoic acid.

Take Test
Q.134 Medium Organic Chemistry
The reaction of acetyl chloride with aniline preferentially gives N-acetylaniline rather than p-acetylaniline because:
A Nitrogen is more nucleophilic than benzene ring
B Acetyl chloride reacts with acyl group
C The product is kinetically favored
D Aniline acts as an electrophile
Correct Answer:  A. Nitrogen is more nucleophilic than benzene ring
EXPLANATION

The lone pair on nitrogen of aniline is more nucleophilic than the π electrons of benzene, making N-acylation the dominant pathway.

Take Test
Q.135 Medium Organic Chemistry
In the nitration of anisole (C6H5-O-CH3), the major product is:
A 2-nitroanisole
B 3-nitroanisole
C 4-nitroanisole
D 2,4-dinitroanisole
Correct Answer:  A. 2-nitroanisole
EXPLANATION

Methoxy group is ortho-para directing and activating. Due to steric hindrance at para position, 2-nitroanisole is the major product.

Take Test
Q.136 Medium Organic Chemistry
Which of the following compounds will not give a positive Iodoform test?
A CH3-CH2-CH(OH)-CH3
B CH3-CO-CH3
C C6H5-CH2-CH(OH)-CH3
D CH3-CH2-OH
Correct Answer:  D. CH3-CH2-OH
EXPLANATION

Iodoform test requires either a methyl ketone (COCH3) or secondary alcohol with CH3 adjacent to CHOH. Ethanol has no such structure.

Take Test
Q.137 Medium Organic Chemistry
The pKa of phenol (C6H5OH) is approximately 10, while that of aliphatic alcohol is around 16. This difference is due to:
A Greater electronegativity of aromatic carbon
B Resonance stabilization of phenoxide ion through benzene ring
C Inductive effect of benzene ring
D Hydrogen bonding in phenol
Correct Answer:  B. Resonance stabilization of phenoxide ion through benzene ring
EXPLANATION

Phenoxide ion is stabilized by resonance with the benzene ring, making phenol more acidic than aliphatic alcohols.

Take Test
Q.138 Medium Organic Chemistry
In the Friedel-Crafts alkylation of benzene with 1-chloropropane and AlCl3, the major product is isopropylbenzene due to:
A Formation of secondary carbocation which rearranges to tertiary
B Direct formation of tertiary carbocation
C SN2 mechanism preference
D Formation of primary carbocation
Correct Answer:  A. Formation of secondary carbocation which rearranges to tertiary
EXPLANATION

Primary carbocation rearranges via hydride shift to form more stable secondary carbocation, which then forms isopropylbenzene.

Take Test
Q.139 Medium Organic Chemistry
The Wittig reaction converts a carbonyl compound into:
A An amine
B An alkene
C An alcohol
D An ether
Correct Answer:  B. An alkene
EXPLANATION

The Wittig reaction uses a phosphonium ylide to convert carbonyl compounds (aldehydes and ketones) to alkenes. It's valuable for forming C=C double bonds with defined positions.

Take Test
Q.140 Medium Organic Chemistry
In the reaction of acetylene with HgSO4/H2SO4, the product is:
A Acetaldehyde
B Ethanol
C Acetic acid
D Acetone
Correct Answer:  A. Acetaldehyde
EXPLANATION

This is the hydration of alkynes using Hg2+ catalyst. Acetylene (HC≡CH) undergoes hydration to form acetaldehyde (CH3CHO) via enol intermediate, which tautomerizes.

Take Test
IGET
iget AI
Online · Ask anything about exams
Hi! 👋 I'm your iget AI assistant.

Ask me anything about exam prep, MCQ solutions, study tips, or strategies! 🎯
UPSC strategy SSC CGL syllabus Improve aptitude NEET Biology tips