Govt Exams
Let manufacturer's CP = x. Wholesaler's CP = 1.2x. Retailer's CP = 1.2x × 1.25 = 1.5x. Customer pays = 1.5x × 1.3 = 1.95x = 1,950. So x = 1,000.
After 30% discount: 1500 × 0.7 = ₹1050. After additional 10%: 1050 × 0.9 = ₹945
Filling rate = 1/10, Emptying rate = 1/15. Net rate = 1/10 - 1/15 = 3/30 - 2/30 = 1/30. Time = 30 hours
Let numbers be 4k and 5k. HCF = k = 8. So numbers are 32 and 40
SP1 = 1000 × 1.2 = ₹1200. SP2 = 1000 × 0.8 = ₹800. Total SP = 2000. Total CP = 2000. Loss = 2000 - 1600 = ₹400. Wait, recalculating: Total SP = 2000, Total CP = 2000. No net = 0. Actually: When profit% = loss%, overall is always loss = (r/100)^2 × 100 = (20/100)^2 × 100 = 4% loss
Amount = P(1 + r/100)^t = 8000(1.1)^2 = 8000 × 1.21 = ₹9680. CI = 9680 - 8000 = ₹1680
96 = 2^5 × 3, 144 = 2^4 × 3^2, 192 = 2^6 × 3. HCF = 2^4 × 3 = 16 × 3 = 48
Downstream speed = 48/3 = 16 km/h. Upstream speed = 24/4 = 6 km/h. Speed in still water = (16+6)/2 = 11 km/h. (Closest option A is 10, likely ₹typo in question setup)
Speed = 60 km/h = 60 × 5/18 = 50/3 m/s. Distance covered = (50/3) × 30 = 500m. This is train length + platform length. Train length = 500 - 300 = 200m. Wait, recalculating: Distance = Speed × Time = (60×1000/3600) × 30 = 16.67 × 30 = 500m = Length of train + platform. Train length = 500 - 300 = 200m. Correction: The answer should be 200m
For HCF=18 and LCM=432, the possible pairs are (18,432), (36,216), (54,144). Total = 3 pairs