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JEE Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

225 Q 5 Topics Take Test
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Difficulty: All Easy Medium Hard 151–160 of 225
Topics in JEE Chemistry
Q.151 Medium Organic Chemistry
In the addition of HBr to propene, the major product is 2-bromopropane because of:
A Le Chatelier's principle
B Markovnikov's rule
C Anti-Markovnikov addition
D Hydrogen preference
Correct Answer:  B. Markovnikov's rule
EXPLANATION

Markovnikov's rule states that in addition to unsymmetrical alkenes, the hydrogen adds to the carbon with more hydrogen atoms, and the addendum to the carbon with fewer hydrogens, forming the more stable carbocation intermediate.

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Q.152 Medium Organic Chemistry
The reactivity order of alkyl halides in SN1 reactions is:
A Primary > Secondary > Tertiary
B Tertiary > Secondary > Primary
C Secondary > Primary > Tertiary
D All are equally reactive
Correct Answer:  B. Tertiary > Secondary > Primary
EXPLANATION

SN1 proceeds through carbocation formation. Tertiary carbocations are most stable (hyperconjugation and inductive effects), followed by secondary, then primary.

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Q.153 Medium Organic Chemistry
A chiral compound with the structure CH3-CHBr-CH(OH)-CH3 will have how many stereoisomers?
A 2
B 4
C 8
D 16
Correct Answer:  B. 4
EXPLANATION

The molecule has two chiral centers (carbons bearing Br and OH). Each chiral center can have R or S configuration, giving 2² = 4 possible stereoisomers (diastereomers and enantiomers).

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Q.154 Medium Organic Chemistry
In the conversion of benzene to benzoic acid through the Kolbe reaction, the carboxylic acid is ultimately derived from:
A The phenolic oxygen
B CO2 fixation on the aromatic ring
C Oxidation of a side chain
D Displacement of a leaving group on the ring
Correct Answer:  B. CO2 fixation on the aromatic ring
EXPLANATION

In the Kolbe carboxylation of phenols, CO2 is directly incorporated into the aromatic ring ortho to the hydroxyl group under high temperature and pressure with alkali, forming salicylic acid derivatives.

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Q.155 Medium Organic Chemistry
The rate of E1 elimination reaction depends on:
A Concentration of both substrate and base
B Concentration of substrate only
C Concentration of base only
D Temperature but not concentrations
Correct Answer:  B. Concentration of substrate only
EXPLANATION

E1 elimination is a two-step mechanism where the rate-determining step is the formation of carbocation (unimolecular). The rate depends only on substrate concentration, following first-order kinetics.

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Q.156 Medium Organic Chemistry
Which statement about aldol condensation is correct?
A Both carbonyl compounds must be aldehydes
B It requires a strong acid catalyst
C A compound with α-hydrogen can serve as the enolate donor
D The reaction is irreversible under all conditions
Correct Answer:  C. A compound with α-hydrogen can serve as the enolate donor
EXPLANATION

Aldol condensation requires a compound with α-hydrogens that can form an enolate/enol as the nucleophilic component, and a carbonyl compound as the electrophile. Ketones can also be used.

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Q.157 Medium Organic Chemistry
The reaction of benzene with excess Cl2 in the presence of FeCl3 followed by hydrolysis gives:
A Chlorobenzene only
B Polychlorobenzene mixture
C Benzene diol
D Phenol
Correct Answer:  B. Polychlorobenzene mixture
EXPLANATION

Chlorobenzene formed initially is more deactivated than benzene, but further chlorination can occur at ortho/para positions under excess Cl2 conditions, yielding a mixture of polychlorobenzenes.

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Q.158 Medium Organic Chemistry
Which of the following carboxylic acids is most acidic?
A CH3-COOH
B CF3-COOH
C CCl3-COOH
D CBr3-COOH
Correct Answer:  B. CF3-COOH
EXPLANATION

CF3-COOH is most acidic because fluorine is highly electronegative and strongly withdraws electron density through inductive effects, stabilizing the conjugate base carboxylate ion.

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Q.159 Medium Organic Chemistry
In the preparation of phenol from cumene (isopropylbenzene), the intermediate cumene hydroperoxide is cleaved in acidic conditions to give:
A Phenol and formaldehyde
B Phenol and acetone
C Benzene and isopropanol
D Phenol and propene
Correct Answer:  B. Phenol and acetone
EXPLANATION

The cumene hydroperoxide undergoes an acid-catalyzed rearrangement (Hock rearrangement) where the isopropyl group rearranges to give phenol and acetone as the cleavage products.

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Q.160 Medium Organic Chemistry
Which isomer of dimethylbenzene (xylene) will show only 2 signals in 1H-NMR?
A ortho-xylene
B meta-xylene
C para-xylene
D All show 2 signals
Correct Answer:  C. para-xylene
EXPLANATION

Para-xylene has high symmetry: all four aromatic protons are equivalent (one signal) and all six methyl protons are equivalent (one signal), giving only 2 total signals in 1H-NMR.

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