Govt Exams
ΔG° = -nFE° = -2 × 96500 × 1.1 = -212300 J/mol = -212.3 kJ/mol
Cathode is where reduction occurs. It's the positive electrode in a galvanic cell as it attracts cations.
Using Henderson-Hasselbalch: pH = pKa + log([A⁻]/[HA]) = 4.74 + log(0.1/0.1) = 4.74
For exothermic reactions, increasing temperature decreases Kc (unfavorable) and shifts equilibrium left (Le Chatelier's principle).
i = π/(MRT) = 2.46/(0.1 × 0.0821 × 273) ≈ 1. Glucose is non-electrolyte with i = 1
Using Henderson-Hasselbalch equation: pH = pKa + log([salt]/[acid]) = 4.74 + log(0.1/0.1) = 4.74 + 0 = 4.74.
ΔS = ΔH/T = (6000 J/mol) / 273 K = 22.0 J/(mol·K). For 18 g (1 mole) of ice, ΔS = 22.0 J/K.
For second-order reactions, t₁/₂ = 1/(k[A₀]) = 1/(0.5 × 2) = 1.0 s.
ΔG° = -nFE° = -2 × 96500 × 1.10 = -212,300 J/mol = -212.3 kJ/mol.
For a reversible adiabatic process, q = 0 and ΔS = 0 because there is no heat exchange and the process is reversible, making it isentropic.