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JEE Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

225 Q 5 Topics Take Test
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Difficulty: All Easy Medium Hard 191–200 of 225
Topics in JEE Chemistry
Q.191 Medium Physical Chemistry
Using Nernst equation at 25°C, if E°cell = 1.10 V and the reaction quotient Q = 100, what is Ecell for the reaction Cu + Zn²⁺ → Cu²⁺ + Zn?
A 1.04 V
B 1.16 V
C 0.94 V
D 1.26 V
Correct Answer:  C. 0.94 V
EXPLANATION

Ecell = E°cell - (0.0592/n)log Q = 1.10 - (0.0592/2)log(100) = 1.10 - 0.0592 × 2 = 1.10 - 0.1184 ≈ 0.98 V ≈ 0.94 V (nearest option).

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Q.192 Medium Physical Chemistry
The standard entropy change (ΔS°) for a reaction is -150 J/mol·K and ΔH° = -200 kJ/mol. Below what temperature will this reaction be spontaneous?
A 667 K
B 1333 K
C 75 K
D 0.75 K
Correct Answer:  B. 1333 K
EXPLANATION

For spontaneity: ΔG° < 0. ΔG° = ΔH° - TΔS°. At equilibrium: 0 = -200,000 - T(-150), giving T = 200,000/150 ≈ 1333 K. Reaction is spontaneous below this temperature.

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Q.193 Medium Physical Chemistry
What is the coefficient of x in the van 't Hoff equation: d(ln Kp)/dT = ΔH°/RT²?
A ΔH° is independent of T
B ΔH° varies linearly with T
C ΔH° varies exponentially with T
D ΔH° is zero
Correct Answer:  A. ΔH° is independent of T
EXPLANATION

The van 't Hoff equation assumes ΔH° is independent of temperature over the range studied. This is the basis for the integrated form: ln(K₂/K₁) = (ΔH°/R)(1/T₁ - 1/T₂).

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Q.194 Medium Physical Chemistry
For the equilibrium: H₂(g) + I₂(g) ⇌ 2HI(g), Kc = 50 at 400°C. If initial concentrations are [H₂] = 1 M, [I₂] = 1 M, [HI] = 0, what is the equilibrium concentration of HI?
A 0.82 M
B 1.64 M
C 0.91 M
D 1.82 M
Correct Answer:  B. 1.64 M
EXPLANATION

Using ICE table: Let x be change. At equilibrium: Kc = (2x)²/((1-x)(1-x)) = 50. Solving: 4x² = 50(1-x)², gives x ≈ 0.82. [HI] = 2x ≈ 1.64 M.

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Q.195 Medium Physical Chemistry
A reaction mechanism consists of: Step 1 (slow): A + B → C; Step 2 (fast): C + D → E. The overall reaction is A + B + D → E. What is the rate law?
A Rate = k[A][B][D]
B Rate = k[A][B]
C Rate = k[C][D]
D Rate = k[A]²[B]
Correct Answer:  B. Rate = k[A][B]
EXPLANATION

Rate law depends on the rate-determining step (slowest step). Step 1 is slow: A + B → C, so Rate = k[A][B]. The fast step doesn't appear in the rate law unless intermediates need elimination.

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Q.196 Medium Physical Chemistry
The decomposition of H₂O₂ follows first-order kinetics with k = 1.4 × 10⁻³ min⁻¹. What is the half-life of H₂O₂?
A 495 min
B 250 min
C 500 min
D 1000 min
Correct Answer:  A. 495 min
EXPLANATION

For first-order reaction: t₁/₂ = 0.693/k = 0.693/(1.4 × 10⁻³) ≈ 495 min. Half-life is independent of initial concentration for first-order reactions.

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Q.197 Medium Physical Chemistry
The rate constant for a reaction doubles when temperature increases from 27°C to 37°C. What is the activation energy (Ea) for this reaction? (Given: R = 8.314 J/mol·K)
A 52.85 kJ/mol
B 105.7 kJ/mol
C 210 kJ/mol
D 26.4 kJ/mol
Correct Answer:  A. 52.85 kJ/mol
EXPLANATION

Using Arrhenius equation: ln(k₂/k₁) = (Ea/R)(1/T₁ - 1/T₂). With k₂/k₁ = 2, T₁ = 300K, T₂ = 310K: ln(2) = (Ea/8.314)(1/300 - 1/310). Solving gives Ea ≈ 52.85 kJ/mol.

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Q.198 Medium Physical Chemistry
For a reaction mechanism with a rate-determining slow step, which statement is correct?
A The overall reaction rate equals the rate of the fastest step
B The overall reaction rate equals the rate of the slowest step
C The overall reaction rate is the sum of all individual step rates
D The overall reaction rate is independent of the mechanism
Correct Answer:  B. The overall reaction rate equals the rate of the slowest step
EXPLANATION

The rate-determining step (slowest step) controls the overall reaction rate. The RDS is the bottleneck that limits how fast reactants can be converted to products.

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Q.199 Medium Physical Chemistry
A galvanic cell is constructed using Zn/Zn²⁺ (E° = -0.76 V) and Cu/Cu²⁺ (E° = +0.34 V) electrodes. What is the standard cell potential?
A 0.42 V
B 1.10 V
C 0.58 V
D -1.10 V
Correct Answer:  B. 1.10 V
EXPLANATION

E°cell = E°cathode - E°anode = 0.34 - (-0.76) = 0.34 + 0.76 = 1.10 V. Cu²⁺/Cu is cathode (reduction), Zn²⁺/Zn is anode (oxidation).

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Q.200 Medium Physical Chemistry
Which of the following represents a second-order reaction with respect to reactant A?
A Rate = k[A]
B Rate = k[A]²
C 1/[A] = kt + 1/[A]₀
D ln[A] = -kt + ln[A]₀
Correct Answer:  C. 1/[A] = kt + 1/[A]₀
EXPLANATION

The integrated rate law for a second-order reaction is 1/[A] = kt + 1/[A]₀. Option B shows rate law (differential form), option D shows first-order integrated rate law.

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