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JEE Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

225 Q 5 Topics Take Test
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Difficulty: All Easy Medium Hard 221–225 of 225
Topics in JEE Chemistry
Q.221 Medium Physical Chemistry
In a electrochemical cell, the standard cell potential E°cell = 0.34 V. The value of ΔG° at 298 K is approximately: (F = 96500 C/mol)
A -32.8 kJ/mol
B -65.6 kJ/mol
C -98.4 kJ/mol
D -131.2 kJ/mol
Correct Answer:  B. -65.6 kJ/mol
EXPLANATION

ΔG° = -nFE°cell. For n=2 (typical): ΔG° = -2 × 96500 × 0.34 = -65,620 J/mol ≈ -65.6 kJ/mol.

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Q.222 Medium Physical Chemistry
The Henry's law constant for CO₂ in water at 25°C is approximately:
A 1.67 × 10³ atm/(mol/L)
B 2.5 × 10⁻⁴ atm/(mol/L)
C 1.67 × 10⁻³ atm/(mol/L)
D 3.5 × 10² atm/(mol/L)
Correct Answer:  A. 1.67 × 10³ atm/(mol/L)
EXPLANATION

Henry's law constant for CO₂ in water at 25°C is Kh ≈ 1.67 × 10³ atm·L/mol, used as P = Kh·x.

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Q.223 Medium Physical Chemistry
For an ideal gas undergoing isothermal expansion, the work done by gas is:
A Zero
B nRT ln(Vf/Vi)
C nRT ln(Vi/Vf)
D ΔU
Correct Answer:  B. nRT ln(Vf/Vi)
EXPLANATION

For isothermal process: W = nRT ln(Vf/Vi). Since Vf > Vi, work done by gas is positive.

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Q.224 Medium Physical Chemistry
The rate constant of a reaction at 25°C is k₁ and at 75°C is k₂. If Ea = 60 kJ/mol, what is k₂/k₁? (R = 8.314 J/mol·K)
A 10.3
B 25.8
C 103
D 258
Correct Answer:  C. 103
EXPLANATION

Using Arrhenius equation: ln(k₂/k₁) = (Ea/R)(1/T₁ - 1/T₂) = (60000/8.314)(1/298 - 1/348) ≈ 4.63, so k₂/k₁ ≈ 103.

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Q.225 Medium Physical Chemistry
At critical point, the compressibility factor Z equals:
A 1
B 0.5
C 0.27
D 2
Correct Answer:  C. 0.27
EXPLANATION

At the critical point, Z = PcVc/RTc = 0.27 for most real gases (theoretical value for van der Waals gas).

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