NEET Chemistry

Chemistry questions for NEET UG — Physical, Organic, Inorganic Chemistry.

41 Q 1 Topics Take Test

Difficulty: All Easy Medium Hard 41–41 of 41

Topics in NEET Chemistry

Q.41 Medium Physical Chemistry

A buffer solution is prepared by mixing 100 mL of 0.1 M acetic acid (CH₃COOH) and 100 mL of 0.1 M sodium acetate (CH₃COONa). Using Henderson-Hasselbalch equation, if Ka = 1.8 × 10⁻⁵, what is the pH?

A 3.74

B 4.74

C 5.74

D 6.74

Correct Answer: B. 4.74

EXPLANATION

pH = pKa + log([A⁻]/[HA]). pKa = -log(1.8 × 10⁻⁵) ≈ 4.74. Since [A⁻] = [HA] (equal concentrations), log(1) = 0. Therefore, pH = 4.74.

Take Test

1…3 4 5

All Subjects & Topics

Medical & Engg

Govt Exams

Teacher Exams

Subjects

Quick Links

NEET Chemistry