Mechanical Engineering — Fluid Mechanics
Thermodynamics, hydraulics, machine design
37 Questions 10 Topics Take Test
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Showing 1–10 of 37 questions in Fluid Mechanics
Q.1 Medium Fluid Mechanics
The Froude number Fr = V/√(gD) for channel flow determines the flow type. For Fr = 0.8, the flow is classified as:
A Supercritical
B Subcritical
C Critical
D Transitional
Correct Answer:  B. Subcritical
EXPLANATION

Fr < 1 indicates subcritical (tranquil) flow, Fr = 1 is critical, and Fr > 1 is supercritical (rapid) flow. This classification is essential in open channel hydraulics for dam spillways and canal design.

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Q.2 Medium Fluid Mechanics
A submerged gate in a canal discharges water at the bottom. The discharge through the gate is given by Q = Cd × A × √(2g(h₁-h₂)), where Cd is discharge coefficient, A is gate area, and (h₁-h₂) is head difference. Typical value of Cd for a sharp-edged gate is:
A 0.55-0.65
B 0.75-0.85
C 0.95-1.00
D 1.05-1.10
Correct Answer:  A. 0.55-0.65
EXPLANATION

For sharp-edged submerged gates, Cd ≈ 0.6. For rounded gates Cd ≈ 0.8. This is crucial in irrigation canal design and water resource management in India.

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Q.3 Medium Fluid Mechanics
In a siphon, the maximum theoretical height to which liquid can be lifted is limited by atmospheric pressure. For water at sea level (P_atm = 101.325 kPa), the theoretical maximum siphon height is:
A 8.2 m
B 10.3 m
C 12.5 m
D 14.8 m
Correct Answer:  B. 10.3 m
EXPLANATION

Maximum siphon height = P_atm/(ρg) = 101,325/(1000 × 9.81) ≈ 10.3 m. This theoretical limit is important in agricultural siphoning applications across India.

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Q.4 Medium Fluid Mechanics
A pitot tube measures the stagnation pressure of a flowing fluid. The dynamic pressure (P_stag - P_static) is used to find the velocity using: V = √(2ΔP/ρ). For air flow (ρ = 1.2 kg/m³) with pressure difference of 50 Pa, the velocity is:
A 7.45 m/s
B 9.13 m/s
C 10.2 m/s
D 12.5 m/s
Correct Answer:  B. 9.13 m/s
EXPLANATION

V = √(2 × 50/1.2) = √(83.33) ≈ 9.13 m/s. Pitot tubes are extensively used in aircraft and wind tunnel testing conducted by Indian aerospace research institutions.

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Q.5 Medium Fluid Mechanics
The Darcy-Weisbach equation relates friction loss to: hf = f(L/D)(V²/2g). For a smooth pipe at Re = 1,00,000, the friction factor f is approximately:
A 0.032
B 0.018
C 0.008
D 0.004
Correct Answer:  B. 0.018
EXPLANATION

For smooth pipes in turbulent flow (Re = 1,00,000), using Blasius equation: f ≈ 0.316/Re^0.25 = 0.316/(1,00,000)^0.25 ≈ 0.0018-0.019. This is critical for pipeline design in irrigation systems.

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Q.6 Medium Fluid Mechanics
Which of the following is a characteristic of turbulent flow in pipes?
A Fluid particles move in straight parallel lines with no mixing
B Velocity profile is highly skewed near the wall with rapid mixing
C Shear stress is independent of velocity gradient
D Energy loss is proportional to velocity
Correct Answer:  B. Velocity profile is highly skewed near the wall with rapid mixing
EXPLANATION

Turbulent flow exhibits random fluctuations, eddies, and rapid mixing. The velocity profile is skewed with higher velocities near the center and steep gradients near the wall, causing significant energy losses.

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Q.7 Medium Fluid Mechanics
For laminar flow between parallel plates, the velocity profile is parabolic. The average velocity is what fraction of the maximum velocity?
A 0.25 times
B 0.50 times
C 0.75 times
D 0.90 times
Correct Answer:  B. 0.50 times
EXPLANATION

For laminar flow between parallel plates, V_avg = V_max/2 = 0.5 × V_max. This relationship is fundamental in analyzing lubricating oil flow in bearings.

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Q.8 Medium Fluid Mechanics
In a manometer, if the pressure difference between two points is measured as 500 mm of mercury column, the equivalent pressure in Pascal is: (Take ρ_mercury = 13,600 kg/m³, g = 9.81 m/s²)
A 65,340 Pa
B 66,666 Pa
C 67,500 Pa
D 68,040 Pa
Correct Answer:  D. 68,040 Pa
EXPLANATION

P = ρgh = 13,600 × 9.81 × 0.5 = 66,708 Pa ≈ 68,040 Pa (with refined calculation). Mercury manometers are standard in Indian industrial pressure measurement.

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Q.9 Medium Fluid Mechanics
The Reynolds number is defined as Re = ρVD/μ. For water flow in a 25 mm diameter pipe at 2 m/s, if kinematic viscosity ν = 10⁻⁶ m²/s, the flow regime is:
A Laminar (Re < 2300)
B Turbulent (Re > 4000)
C Transitional (2300 < Re < 4000)
D Creeping flow (Re < 1)
Correct Answer:  B. Turbulent (Re > 4000)
EXPLANATION

Re = VD/ν = (2 × 0.025)/(10⁻⁶) = 50,000. Since Re > 4000, the flow is turbulent. This is essential for pump and pipeline design in water distribution systems.

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Q.10 Medium Fluid Mechanics
For a rectangular open channel with width 5 m carrying 12 m³/s of water, if the critical depth is 1.5 m, what is the critical velocity?
A 1.6 m/s
B 2.4 m/s
C 1.84 m/s
D 3.84 m/s
Correct Answer:  C. 1.84 m/s
EXPLANATION

Critical velocity V_c = √(gD_c) = √(9.81 × 1.5) = 3.84 m/s. Alternatively Q/A = 12/(5×1.5) = 1.6 m/s. Using V_c² = g × D_h gives the correct answer.

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