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Mechanical Engineering

Thermodynamics, hydraulics, machine design

179 Q 2 Topics Take Test
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Difficulty: All Easy Medium Hard 131–140 of 179
Topics in Mechanical Engineering
All Thermodynamics 100 Fluid Mechanics 79
Q.131 Medium Thermodynamics
In a turbocharger application, compressed air enters a turbine. If the isentropic efficiency of the turbine is 0.85, what does this indicate?
A 85% of input heat is converted to work
B Actual work output is 85% of isentropic work output
C 85% of the system is reversible
D The process is 85% adiabatic
Correct Answer:  B. Actual work output is 85% of isentropic work output
EXPLANATION

Isentropic efficiency = Actual work output / Isentropic work output = 0.85. It compares real process with ideal isentropic process.

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Q.132 Easy Thermodynamics
A system undergoes a cyclic process. The net work done by the system is 150 kJ and the net heat absorbed is 150 kJ. Which statement is correct?
A The process violates the first law of thermodynamics
B The process obeys the first law; ΔU_cycle = 0
C The surroundings have done negative work on the system
D The internal energy of the system has increased by 300 kJ
Correct Answer:  B. The process obeys the first law; ΔU_cycle = 0
EXPLANATION

For any cycle: ΔU_cycle = 0. First law: Q_net = W_net confirms energy conservation. 150 = 150 ✓

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Q.133 Medium Thermodynamics
During throttling of a real gas through an expansion valve, which thermodynamic property remains constant?
A Temperature
B Entropy
C Enthalpy
D Internal energy
Correct Answer:  C. Enthalpy
EXPLANATION

Throttling is an isenthalpic process (constant enthalpy). Temperature may change for real gases due to Joule-Thomson effect.

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Q.134 Easy Thermodynamics
If the specific heat at constant volume (Cv) for a diatomic ideal gas is 5R/2, what is its specific heat at constant pressure (Cp)?
A 7R/2
B 5R/2
C 3R/2
D 9R/2
Correct Answer:  A. 7R/2
EXPLANATION

Using Mayer's relation: Cp - Cv = R. Therefore, Cp = 5R/2 + R = 7R/2

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Q.135 Hard Thermodynamics
A Rankine cycle (ideal steam cycle) is used in thermal power plants. Which process has the highest irreversibility?
A Isentropic expansion in turbine
B Isobaric heat addition in boiler
C Isobaric heat rejection in condenser
D Isentropic compression in pump
Correct Answer:  B. Isobaric heat addition in boiler
EXPLANATION

Heat transfer across finite temperature differences in the boiler creates maximum entropy generation and irreversibility among the four processes.

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Q.136 Hard Thermodynamics
For a closed system undergoing a reversible isothermal process, the change in Gibbs free energy (ΔG) is:
A Always positive
B Equal to the heat absorbed by the system
C Equal to the maximum useful work that can be extracted
D Always zero
Correct Answer:  C. Equal to the maximum useful work that can be extracted
EXPLANATION

For isothermal process: ΔG = ΔH - TΔS = W_useful (non-PV work). This represents maximum useful work available.

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Q.137 Easy Thermodynamics
What is the SI unit of entropy?
A J/K
B J·K
C kJ/mol
D cal/K
Correct Answer:  A. J/K
EXPLANATION

Entropy is defined as dS = dQ_rev/T. Units: Joules/Kelvin = J/K. This is the fundamental SI unit for entropy.

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Q.138 Medium Thermodynamics
During an adiabatic expansion of an ideal gas, the temperature of the gas decreases. This is because:
A Heat is removed from the gas
B The gas does work on its surroundings, reducing internal energy
C The surroundings do work on the gas
D The gas absorbs heat from surroundings
Correct Answer:  B. The gas does work on its surroundings, reducing internal energy
EXPLANATION

In adiabatic process, Q = 0. From first law: dU = -W. During expansion, W > 0, so dU < 0, meaning internal energy and temperature decrease.

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Q.139 Medium Thermodynamics
Which of the following statements is correct regarding the first law of thermodynamics?
A Energy can be created in an isolated system
B The internal energy of an isolated system can increase indefinitely
C Heat and work are forms of energy transfer, not properties of a system
D Internal energy is path-dependent
Correct Answer:  C. Heat and work are forms of energy transfer, not properties of a system
EXPLANATION

The first law states that dU = Q - W, where heat (Q) and work (W) are energy transfer mechanisms, not state properties. Internal energy (U) is a state property.

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Q.140 Medium Thermodynamics
A reversible heat engine operates between two thermal reservoirs. If the temperature of the hot reservoir is 500 K and the cold reservoir is 300 K, what is the maximum possible efficiency of this engine?
A 40%
B 60%
C 50%
D 75%
Correct Answer:  A. 40%
EXPLANATION

Maximum efficiency occurs in a Carnot engine: η = 1 - (T_cold/T_hot) = 1 - (300/500) = 1 - 0.6 = 0.4 or 40%

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