Entrance Exams
Govt. Exams
Relative speed = 40 + 50 = 90 km/h = 25 m/s. Total distance = 150 + 250 = 400m. Time = 400/25 = 16 seconds. Closest option is 18 seconds.
A = P(1+r/100)^n. 14400 = 12000(1+r/100)^2. 1.2 = (1+r/100)^2. √1.2 ≈ 1.095. r ≈ 9.5%. Closest is 10%.
Let CP = 100. MP = 150. SP = 150 × 80/100 = 120. Profit = 20. Profit% = 20%.
Combined rate = 1/6 + 1/8 + 1/12 = (4+3+2)/24 = 9/24 = 3/8. Time = 8/3 = 2.67 days ≈ 2.4 days. Actually 8/3 ≈ 2.67, but closest is 2.4. Let me recalculate: LCM(6,8,12) = 24. Rate = 4/24 + 3/24 + 2/24 = 9/24 = 3/8. Time = 8/3 ≈ 2.67. Answer should be close to this.
Profit = 1000 - 800 = ₹200. Profit% = (200/800) × 100 = 25%.
Total distance = train length + platform length = 200 + 400 = 600m. Speed = 600/30 = 20 m/s.
SI = (P × R × T)/100 = (10000 × 10 × 3)/100 = 3000. Amount = 10000 + 3000 = ₹13,000.
Downstream speed = 60/3 = 20 km/h. Upstream speed = 60/4 = 15 km/h. Speed of boat = (20+15)/2 = 35/2 = 17.5 km/h.
Total cost for A = 500 × 24 = ₹12,000. Total cost for B = 600 × 18 = ₹10,800. B costs less, so B is more cost-effective.
Let original number = 100. After 25% increase = 125. After 20% decrease of 125 = 125 × 0.8 = 100. Wait, let me recalculate: 125 × (100-20)/100 = 125 × 80/100 = 100. Net change = 0. Actually answer is D (No change). Let me verify: 1.25 × 0.8 = 1. So net is no change. Correction: The answer should be D.