Home Subjects NEET Zoology Genetics & Evolution

NEET Zoology
Genetics & Evolution

Zoology questions for NEET UG — Animal Kingdom, Human Physiology, Genetics, Evolution.

100 Q 6 Topics Take Test
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Difficulty: All Easy Medium Hard 51–60 of 100
Topics in NEET Zoology
A person is heterozygous for cystic fibrosis (Ff). Their partner is homozygous normal (FF). What is the probability of having an affected child?
A 0%
B 25%
C 50%
D 75%
Correct Answer:  A. 0%
EXPLANATION

Cross: Ff × FF produces FF and Ff offspring. All are phenotypically normal. Probability of affected (ff) child = 0%

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Which of the following best represents anagenesis in evolution?
A Splitting of one species into two species
B Gradual transformation of one species into another over time
C Extinction of a species due to environmental change
D Rapid speciation through geographic isolation
Correct Answer:  B. Gradual transformation of one species into another over time
EXPLANATION

Anagenesis refers to phyletic evolution or linear evolution where one species gradually transforms into another without branching.

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A tall plant (genotype unknown) is crossed with a dwarf plant. All offspring are tall. What is the most likely genotype of the tall parent?
A Homozygous dominant (TT)
B Heterozygous (Tt)
C Homozygous recessive (tt)
D Cannot be determined
Correct Answer:  A. Homozygous dominant (TT)
EXPLANATION

All offspring being tall when crossed with dwarf (tt) indicates the tall parent is TT. If it were Tt, approximately half offspring would be dwarf.

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In a population at Hardy-Weinberg equilibrium, if the frequency of recessive allele (q) = 0.3, what is the frequency of heterozygous individuals?
A 0.42
B 0.09
C 0.49
D 0.91
Correct Answer:  A. 0.42
EXPLANATION

If q = 0.3, then p = 0.7. Heterozygous frequency = 2pq = 2(0.7)(0.3) = 0.42

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A gene has four alleles in a population. If three alleles have frequencies of 0.4, 0.3, and 0.2, what is the frequency of the fourth allele?
A 0.1
B 0.5
C 0.9
D 0.6
Correct Answer:  A. 0.1
EXPLANATION

According to Hardy-Weinberg principle, total allele frequencies must equal 1. Therefore, 1 - (0.4 + 0.3 + 0.2) = 0.1

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Which evolutionary evidence involves structural similarities between embryos of different species during early development?
A Molecular homology
B Paleontological evidence
C Embryological evidence
D Biogeographical evidence
Correct Answer:  C. Embryological evidence
EXPLANATION

Embryological similarities, such as gill slits in vertebrate embryos, demonstrate common evolutionary ancestry among different species.

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In human genetics, the ABO blood group is determined by multiple alleles. A person with blood type AB has which genotype?
A IAIA
B IBIb
C IAIB
D ii
Correct Answer:  C. IAIB
EXPLANATION

Type AB blood group is codominant, expressed as IAIB, where both IA and IB alleles are expressed equally.

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A cross between two pea plants produces offspring in the ratio 1:2:1 for a particular trait. This ratio suggests:
A A monohybrid cross between two heterozygous parents
B A testcross between heterozygous and homozygous recessive
C A monohybrid cross between homozygous dominant and homozygous recessive
D A cross between a heterozygous and homozygous dominant
Correct Answer:  A. A monohybrid cross between two heterozygous parents
EXPLANATION

1:2:1 ratio indicates Aa × Aa, where offspring are 1 AA : 2 Aa : 1 aa. This is the typical F2 ratio for a monohybrid cross.

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Which of the following statements about mutations is INCORRECT?
A Mutations are random changes in DNA sequences
B Most mutations are beneficial for organism survival
C Mutations can be induced by UV radiation and chemicals
D Silent mutations do not change amino acid sequences
Correct Answer:  B. Most mutations are beneficial for organism survival
EXPLANATION

Most mutations are either neutral or harmful; only rarely are they beneficial. This is a key principle in evolutionary biology.

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In Drosophila, the gene for white eyes (w) is X-linked recessive. A white-eyed female is crossed with a red-eyed male. What will be the phenotype of F1 females?
A All red-eyed
B All white-eyed
C Half red-eyed, half white-eyed
D All white-eyed with red spots
Correct Answer:  A. All red-eyed
EXPLANATION

White-eyed female (XwXw) × red-eyed male (XWY). F1 females receive Xw from mother and XW from father, making them XWXw (red-eyed carriers).

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