Govt Exams
H→I(+1), E→F(+1), A→B(+1), R→S(+1), T→U(+1). Each letter is shifted forward by 1 position.
While we know P is lowest and relative positions of others, Q's exact position relative to all students cannot be uniquely determined from given constraints.
Pattern: Letters progress forward and backward (A→E, Z→V). Numbers: 2, 4, 6, 8, 10 (even numbers). Next: E10V.
With Ring at box 3, Pen-Chain in consecutive positions (boxes 1-2 or 4-5), Watch not at 1 or 5, and Locket not at 2 or 4, only 2 arrangements satisfy all constraints.
Teacher provides/works in education; doctor provides/works in medicine. The relationship is profession to field.
The middle term 'polygons' is not distributed in either premise, so no valid conclusion can be drawn.
Each number is multiplied by 3. 8×3=24, 24×3=72, 72×3=216, 216×3=648.
P=16, E=5, N=14: 16+5+14=35×2=70? Rechecking: If each letter = position value, PEN=16+5+14=35. If coded as 80, factor is 80/35≈2.29. Using A=1...Z=26: P(16)+E(5)+N(14)=35. NET=N(14)+E(5)+T(20)=39. If NET=65, then 65/39≈1.67. TEN=T(20)+E(5)+N(14)=39. Using ratio from NET: 39×(65/39)=65? Or TEN=60 by different pattern.
With A opposite D, B between A and F, E to right of A, and C not adjacent to A, there are 2 valid arrangements satisfying all constraints.
North 5, then south 5 cancels out. East 3, then west 2 = 1 km east net displacement.