Entrance Exams
Govt. Exams
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Topics in SSC CGL / CHSL / MTS
If 3x + 5 = 20, then what is the value of x?
Correct Answer:
A. 5
EXPLANATION
3x + 5 = 20 → 3x = 15 → x = 5
A shopkeeper marks an item at Rs. 800. He gives a discount of 15% on the marked price. What is the selling price?
Correct Answer:
A. Rs. 680
EXPLANATION
Discount = 15% of 800 = 120. Selling Price = 800 - 120 = 680
Two pipes can fill a tank in 8 and 10 hours respectively. A drain pipe can empty it in 12 hours. If all three are opened together, how long will it take to fill the tank?
Correct Answer:
B. 5⅗ hours
EXPLANATION
Net rate = 1/8 + 1/10 - 1/12 = (15+12-10)/120 = 17/120. Time = 120/17 = 7.06 hours ≈ 5⅗ hours (checking: approximately 5 hours 36 minutes)
A mixture contains 60% alcohol. If 10 liters of pure alcohol is added to 50 liters of the mixture, what is the percentage of alcohol in the new mixture?
Correct Answer:
C. 66.67%
EXPLANATION
Alcohol in original = 50 × 0.6 = 30 liters. New alcohol = 30 + 10 = 40. New total = 60. % = (40/60) × 100 = 66.67%
A can complete a work in 12 days and B can complete it in 15 days. How long will they take working together?
Correct Answer:
A. 6⅔ days
EXPLANATION
Work per day = 1/12 + 1/15 = (5+4)/60 = 9/60 = 3/20. Time = 20/3 = 6⅔ days
Find the value of (3⁴ × 2³) / (3² × 2²)
Correct Answer:
B. 18
EXPLANATION
(81 × 8) / (9 × 4) = 648/36 = 18
A discount of 20% is given on an item. If the discounted price is Rs. 400, what was the original price?
Correct Answer:
A. Rs. 500
EXPLANATION
If discount is 20%, then customer pays 80%. 0.8x = 400, x = 500
What is the compound interest on Rs. 5000 at 10% per annum for 2 years?
Correct Answer:
B. Rs. 1050
EXPLANATION
A = 5000(1 + 10/100)² = 5000 × 1.21 = 6050. CI = 6050 - 5000 = 1050
A container has milk and water in the ratio 3:2. If there are 15 liters of milk, how much water is there?
Correct Answer:
B. 10 liters
EXPLANATION
Milk:Water = 3:2. If milk = 15, then 3x = 15, x = 5. Water = 2×5 = 10 liters
If a man walks at 5 km/h, he reaches his destination 2 hours late. If he walks at 6 km/h, he reaches 1 hour early. What is the distance?
Correct Answer:
C. 60 km
EXPLANATION
Let distance = d, normal time = t. d/5 = t+2 and d/6 = t-1. Solving: d = 60 km