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Quantitative Aptitude

Quantitative aptitude questions for competitive exams

1,106 Q 7 Topics Take Test
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Difficulty: All Easy Medium Hard 961–970 of 1,106
Topics in Quantitative Aptitude
Q.961 Easy Time and Work
B can do a job in 15 days. What is B's work rate per day?
A 1/10
B 1/15
C 1/20
D 1/25
Correct Answer:  B. 1/15
EXPLANATION

This question asks us to find B's daily work rate when the total job can be completed in 15 days.

Step 1: Understand work rate definition

Work rate is the fraction of total work completed per day.

\[\text{Work Rate} = \frac{\text{Total Work}}{\text{Total Days}}\]
Step 2: Define total work as 1 complete job

Since B completes the entire job, the total work equals 1.

\[\text{Total Work} = 1\]
Step 3: Calculate B's daily work rate

B completes the job in 15 days, so divide the work by the number of days.

\[\text{B's Work Rate} = \frac{1}{15} \text{ per day}\]

B's work rate is 1/15 of the job per day, which means B completes one-fifteenth of the job each day for 15 days to finish it completely.

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Q.962 Easy Time and Work
A can complete a work in 20 days. How much work will A complete in 5 days?
A 1/5
B 1/4
C 1/3
D 1/2
Correct Answer:  B. 1/4
EXPLANATION

This question tests the concept of work rate and how much work is completed in a given time period.

Step 1: Find A's work rate per day

A completes the entire work in 20 days, so the work rate is 1 part per day.

\[\text{Work rate} = \frac{1}{20} \text{ work per day}\]
Step 2: Calculate work completed in 5 days

Multiply the daily work rate by the number of days.

\[\text{Work completed} = \frac{1}{20} \times 5 = \frac{5}{20}\]
Step 3: Simplify the fraction

Reduce the fraction to its simplest form by dividing both numerator and denominator by 5.

\[\frac{5}{20} = \frac{1}{4}\]

A will complete 1/4 of the work in 5 days.

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Q.963 Hard HCF and LCM
The HCF of two numbers is 12, and their LCM is 240. If the difference between the numbers is 12, find the numbers.
A 24 and 36
B 36 and 48
C 48 and 60
D 60 and 72
Correct Answer:  C. 48 and 60
EXPLANATION

Let numbers be 12a and 12b where HCF(a,b)=1. LCM = 12ab = 240, so ab = 20.

Numbers: 12a and 12b with |12a - 12b| = 12, so |a - b| = 1.

If a=4, b=5: numbers are 48 and 60.

Check: 48-60 = -12 (difference is 12).

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Q.964 Hard HCF and LCM
Three bells ring at intervals of 8, 12, and 16 minutes. If they ring together at 12:00 PM, at what time will they ring together again?
A 12:32 PM
B 12:48 PM
C 1:04 PM
D 1:20 PM
Correct Answer:  B. 12:48 PM
EXPLANATION

Need to find LCM of 8, 12, 16. 8 = 2³, 12 = 2² × 3, 16 = 2⁴. LCM = 2⁴ × 3 = 48 minutes.

So they ring again at 12:00 + 48 min = 12:48 PM.

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Q.965 Medium HCF and LCM
Find the LCM of 84 and 140.
A 420
B 840
C 210
D 280
Correct Answer:  A. 420
EXPLANATION

This question asks us to find the least common multiple (LCM) of two numbers using prime factorization.

Step 1: Find prime factorization of 84

Break 84 into its prime factors by dividing by smallest primes.

\[84 = 2^2 \times 3 \times 7\]
Step 2: Find prime factorization of 140

Break 140 into its prime factors by dividing by smallest primes.

\[140 = 2^2 \times 5 \times 7\]
Step 3: Calculate LCM using highest powers of all prime factors

LCM is found by taking the highest power of each prime factor that appears in either number.

\[\text{LCM} = 2^2 \times 3 \times 5 \times 7 = 4 \times 3 \times 5 \times 7 = 420\]

The LCM of 84 and 140 is 420, which is option (A).

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Q.966 Medium HCF and LCM
What is the HCF of 100, 150, and 200?
A 25
B 50
C 75
D 100
Correct Answer:  B. 50
EXPLANATION

100 = 2² × 5², 150 = 2 × 3 × 5², 200 = 2³ × 5².

Common factors: 2¹ × 5² = 2 × 25 = 50.

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Q.967 Medium HCF and LCM
Two numbers have HCF of 8 and LCM of 96. If one number is 24, find the other number.
A 32
B 40
C 48
D 64
Correct Answer:  A. 32
EXPLANATION

Using formula: HCF × LCM = Product of two numbers. 8 × 96 = 24 × x. 768 = 24x. x = 32.

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Q.968 Medium HCF and LCM
Find the HCF and LCM of 36 and 48. What is their product?
A 1728
B 1440
C 1296
D 1680
Correct Answer:  A. 1728
EXPLANATION

36 = 2² × 3², 48 = 2⁴ × 3. HCF = 2² × 3 = 12, LCM = 2⁴ × 3² = 144.

Product = 36 × 48 = HCF × LCM = 12 × 144 = 1728.

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Q.969 Easy HCF and LCM
The LCM of 15 and 25 is:
A 75
B 150
C 225
D 300
Correct Answer:  A. 75
EXPLANATION

This question asks us to find the Least Common Multiple (LCM) of two numbers using prime factorization.

Step 1: Find prime factorization of 15

Break 15 into its prime factors.

\[15 = 3 \times 5\]
Step 2: Find prime factorization of 25

Break 25 into its prime factors.

\[25 = 5 \times 5 = 5^2\]
Step 3: Calculate LCM using highest powers of all prime factors

The LCM is found by taking the highest power of each prime that appears in either factorization: 3¹ and 5².

\[\text{LCM} = 3^1 \times 5^2 = 3 \times 25 = 75\]

The LCM of 15 and 25 is 75.

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Q.970 Easy HCF and LCM
Find the HCF of 56 and 72.
A 4
B 8
C 12
D 16
Correct Answer:  B. 8
EXPLANATION

This question asks us to find the Highest Common Factor (HCF) of two numbers using prime factorization or the Euclidean algorithm.

Step 1: Prime factorization of 56

Express 56 as a product of prime numbers.

\[56 = 2 \times 2 \times 2 \times 7 = 2^3 \times 7\]
Step 2: Prime factorization of 72

Express 72 as a product of prime numbers.

\[72 = 2 \times 2 \times 2 \times 3 \times 3 = 2^3 \times 3^2\]
Step 3: Find the HCF

The HCF is the product of common prime factors with their lowest powers.

\[\text{HCF} = 2^3 = 8\]

The HCF of 56 and 72 is 8, making the correct answer (B).

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