SI = 10240 - 8000 = 2240. Rate = (2240 × 100)/(8000 × 4) = 7% p.a.

SI₁ = (10000 × 8 × 3)/100 = 2400. SI₂ = (10000 × 10 × 3)/100 = 3000. SI₃ = (10000 × 12 × 3)/100 = 3600. Total = 2400 + 3000 + 3600 = 9000

Q = P[1 + (RT/100)]; Therefore P = Q/[1 + (RT/100)]

Using T = (SI × 100)/(P × R) = (3750 × 100)/(15000 × 7.5) = 3 years

SI paid by A = (5000 × 8 × 3)/100 = 1200. SI received by A = (5000 × 10 × 3)/100 = 1500. Profit = 1500 - 1200 = 300

SI for 4 years = 23,400 - 18,000 = ₹5,400. Rate = (5,400 × 100)/(18,000 × 4) = 7.5% p.a. For 6 years: SI = (18,000 × 7.5 × 6)/100 = ₹8,100. Total Amount = 18,000 + 8,100 = ₹26,100. Wait, recalculating: SI = 5,400 for 4 years, so for 6 years = 5,400 × (6/4) = ₹8,100. Amount = 18,000 + 8,100 = ₹26,100. Check options: For 6 years at 7.5%: Amount = 18,000(1 + 0.075×6) = 18,000 × 1.45 = ₹26,100. Closest is ₹27,000 with recalculation showing SI rate as 7.5%. Actually 28,200: (28,200-18,000)/6 = 10,200/6 = 1,700 per year × 4 years = 6,800 (doesn't match 5,400). For 27,000: SI = 9,000, rate = (9,000×100)/(18,000×6) = 8.33%. Verify with 4 years: (18,000×8.33×4)/100 ≈ 6,000 (not 5,400). Rate from 4 years data: r = (5,400×100)/(18,000×4) = 7.5%. Amount after 6 years = 18,000 + (18,000×7.5×6)/100 = 18,000 + 8,100 = ₹26,100. None match perfectly; closest logical: ₹27,000

Sum of 5 friends = 5 × 24 = 120. Sum of 4 friends = 4 × 22 = 88. Age of friend who left = 120 - 88 = 32 years.

Total cost = (10 × 50) + (15 × 40) = 500 + 600 = 1100. Total items = 25. Average = 1100/25 = ₹44.

Sum of 6 numbers = 6 × 18 = 108. Sum of 3 numbers = 3 × 24 = 72. Total sum = 180. Total numbers = 9. New average = 180/9 = 20.

Total distance = 120 + 180 = 300 km. Total time = 2 + 3 = 5 hours. Average speed = 300/5 = 60 km/h.