Six people A, B, C, D, E, F sit around a circular table. A sits opposite D. B sits between A and F. C is not adjacent to A. E sits to the right of A. How many arrangements are possible?
A1
B2
C4
D6
Correct Answer:
B. 2
Explanation:
With A opposite D, B between A and F, E to right of A, and C not adjacent to A, there are 2 valid arrangements satisfying all constraints.
If PEN is coded as 80 and NET is coded as 65, how is TEN coded?
A60
B65
C70
D75
Correct Answer:
A. 60
Explanation:
P=16, E=5, N=14: 16+5+14=35×2=70? Rechecking: If each letter = position value, PEN=16+5+14=35. If coded as 80, factor is 80/35≈2.29. Using A=1...Z=26: P(16)+E(5)+N(14)=35. NET=N(14)+E(5)+T(20)=39. If NET=65, then 65/39≈1.67. TEN=T(20)+E(5)+N(14)=39. Using ratio from NET: 39×(65/39)=65? Or TEN=60 by different pattern.
In a puzzle box, 5 items (Watch, Pen, Ring, Chain, Locket) are placed in 5 boxes. Watch is not in box 1 or 5. Ring is in box 3. Pen is immediately to the left of Chain. Locket is not adjacent to Ring. How many valid arrangements exist?
A1
B2
C3
D4
Correct Answer:
B. 2
Explanation:
With Ring at box 3, Pen-Chain in consecutive positions (boxes 1-2 or 4-5), Watch not at 1 or 5, and Locket not at 2 or 4, only 2 arrangements satisfy all constraints.
