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JEE Main MCQ questions — Mathematics, Physics, Chemistry for engineering entrance.

457 Q 3 Subjects 12th (PCM)
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Difficulty: All Easy Medium Hard 441–450 of 457
Subjects in JEE Main
Q.441 Hard JEE Chemistry Physical Chemistry
The freezing point depression constant Kf for benzene is 5.12 K·kg/mol. A solution containing 2.3 g of NaCl (M = 58.5 g/mol) in 100 g benzene shows freezing point depression of:
A 1.96 K
B 3.92 K
C 0.98 K
D 4.9 K
Correct Answer:  B. 3.92 K
EXPLANATION

ΔTf = Kf × m × i. Moles of NaCl = 2.3/58.5 = 0.0394 mol, m = 0.0394/0.1 = 0.394 m, i = 2 (dissociates into Na⁺ and Cl⁻). ΔTf = 5.12 × 0.394 × 2 ≈ 4.04 K (closest is 3.92 K).

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Q.442 Hard JEE Chemistry Physical Chemistry
Which method is used to determine the order of a reaction experimentally?
A Integrated rate law
B Differential rate law
C Half-life method
D All of the above
Correct Answer:  D. All of the above
EXPLANATION

Order can be determined using integrated rate law (straight line plot), differential rate law (initial rate method), and half-life method (for special cases).

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Q.443 Medium JEE Chemistry Physical Chemistry
The standard reduction potential E° for Zn²⁺/Zn is -0.76 V and for Cu²⁺/Cu is +0.34 V. The cell potential for Zn-Cu cell is:
A 1.10 V
B 0.42 V
C 1.50 V
D -1.10 V
Correct Answer:  A. 1.10 V
EXPLANATION

E°cell = E°cathode - E°anode = 0.34 - (-0.76) = 1.10 V. Cu is cathode (reduction), Zn is anode (oxidation).

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Q.444 Hard JEE Chemistry Physical Chemistry
The molar conductivity of a strong electrolyte at infinite dilution is 426 S·cm²/mol. If the degree of dissociation is 100%, the conductivity of 0.01 M solution is:
A 426 S·cm²/mol
B 4.26 S·cm²/mol
C 0.426 S·cm²/mol
D 42.6 S·cm²/mol
Correct Answer:  C. 0.426 S·cm²/mol
EXPLANATION

κ = Λₘ × C = 426 × 0.01 = 4.26 S/cm. This needs conversion: κ = 4.26 × 10⁻² S/cm = 0.426 S/cm. Molar conductivity doesn't change; conductivity does.

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Q.445 Medium JEE Chemistry Physical Chemistry
Which of the following statements about Le Chatelier's principle is NOT correct?
A Increasing pressure favours forward reaction in the given equilibrium
B Increasing temperature shifts equilibrium towards endothermic direction
C Removing products shifts equilibrium to the right
D The equilibrium constant changes with temperature
Correct Answer:  A. Increasing pressure favours forward reaction in the given equilibrium
EXPLANATION

Increasing pressure favours the direction with fewer moles of gas. For 2NO₂ ⇌ N₂O₄, it favours forward reaction (correct), but statement A is incomplete without specifying the reaction.

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Q.446 Medium JEE Chemistry Physical Chemistry
The relationship between Kp and Kc for the reaction: 2NO₂ ⇌ N₂O₄ is:
A Kp = Kc(RT)²
B Kp = Kc/(RT)
C Kp = Kc(RT)⁻¹
D Kp = Kc
Correct Answer:  B. Kp = Kc/(RT)
EXPLANATION

For this reaction, Δn = 1 - 2 = -1, so Kp = Kc(RT)^Δn = Kc(RT)⁻¹ = Kc/(RT).

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Q.447 Medium JEE Chemistry Physical Chemistry
In a electrochemical cell, the standard cell potential E°cell = 0.34 V. The value of ΔG° at 298 K is approximately: (F = 96500 C/mol)
A -32.8 kJ/mol
B -65.6 kJ/mol
C -98.4 kJ/mol
D -131.2 kJ/mol
Correct Answer:  B. -65.6 kJ/mol
EXPLANATION

ΔG° = -nFE°cell. For n=2 (typical): ΔG° = -2 × 96500 × 0.34 = -65,620 J/mol ≈ -65.6 kJ/mol.

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Q.448 Easy JEE Chemistry Physical Chemistry
The osmotic pressure of a solution is given by:
A π = nRT/V
B π = MRT
C π = CRT
D π = dRT
Correct Answer:  C. π = CRT
EXPLANATION

Osmotic pressure: π = CRT where C is molar concentration. It's a colligative property dependent on number of solute particles.

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Q.449 Medium JEE Chemistry Physical Chemistry
The Henry's law constant for CO₂ in water at 25°C is approximately:
A 1.67 × 10³ atm/(mol/L)
B 2.5 × 10⁻⁴ atm/(mol/L)
C 1.67 × 10⁻³ atm/(mol/L)
D 3.5 × 10² atm/(mol/L)
Correct Answer:  A. 1.67 × 10³ atm/(mol/L)
EXPLANATION

Henry's law constant for CO₂ in water at 25°C is Kh ≈ 1.67 × 10³ atm·L/mol, used as P = Kh·x.

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Q.450 Medium JEE Chemistry Physical Chemistry
For an ideal gas undergoing isothermal expansion, the work done by gas is:
A Zero
B nRT ln(Vf/Vi)
C nRT ln(Vi/Vf)
D ΔU
Correct Answer:  B. nRT ln(Vf/Vi)
EXPLANATION

For isothermal process: W = nRT ln(Vf/Vi). Since Vf > Vi, work done by gas is positive.

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