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JEE Main MCQ questions — Mathematics, Physics, Chemistry for engineering entrance.

457 Q 3 Subjects 12th (PCM)
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Q.51 Medium JEE Chemistry Chemical Kinetics
Which of the following graphs represents a first-order reaction?
A Plot of [A] vs t is linear
B Plot of ln[A] vs t is linear
C Plot of 1/[A] vs t is linear
D Plot of [A]² vs t is linear
Correct Answer:  B. Plot of ln[A] vs t is linear
EXPLANATION

For a first-order reaction, ln[A] = ln[A]₀ - kt, so a plot of ln[A] vs t gives a straight line with slope -k.

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Q.52 Medium JEE Chemistry Chemical Kinetics
The mechanism of a reaction is: Step 1: A + B → C (slow), Step 2: C + D → E + F (fast). What is the overall reaction and the rate law?
A A + B + D → E + F; rate = k[A][B]
B A + B + D → E + F; rate = k[C][D]
C A + B + C + D → E + F; rate = k[A][B][D]
D A + B → E + F; rate = k[A]²[B]
Correct Answer:  A. A + B + D → E + F; rate = k[A][B]
EXPLANATION

The overall reaction is obtained by adding all steps and canceling intermediates: A + B + D → E + F. Rate law is determined by the slow step: rate = k[A][B]

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Q.53 Medium JEE Chemistry Chemical Kinetics
For a first-order reaction, if the initial concentration is [A]₀ = 0.5 M and after 30 seconds it becomes 0.25 M, what is the rate constant?
A 0.0231 s⁻¹
B 0.0115 s⁻¹
C 0.0462 s⁻¹
D 0.0577 s⁻¹
Correct Answer:  A. 0.0231 s⁻¹
EXPLANATION

Using ln([A]₀/[A]ₜ) = kt, ln(0.5/0.25) = k × 30, ln(2) = k × 30, k = 0.693/30 = 0.0231 s⁻¹

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Q.54 Easy JEE Chemistry Chemical Kinetics
Which of the following statements about activation energy (Eₐ) is correct?
A It is always positive and independent of temperature
B It depends on the direction of the reaction
C It is the minimum energy required for reactants to form products
D It is the total energy of reactants
Correct Answer:  C. It is the minimum energy required for reactants to form products
EXPLANATION

Activation energy is the minimum energy required for reactants to overcome the energy barrier and form products. It is always positive and independent of temperature.

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Q.55 Easy JEE Chemistry Chemical Kinetics
A reaction has a rate constant of k = 2.5 × 10⁻⁴ s⁻¹ at 298 K. What is the order of this reaction if the units of k are s⁻¹?
A Zero order
B First order
C Second order
D Third order
Correct Answer:  B. First order
EXPLANATION

The units s⁻¹ or time⁻¹ indicate a first-order reaction. For first-order reactions, the rate constant has units of time⁻¹.

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Q.56 Easy JEE Chemistry Chemical Kinetics
The half-life of a zero-order reaction is:
A Independent of initial concentration
B Directly proportional to initial concentration
C Inversely proportional to initial concentration
D Logarithmic with respect to initial concentration
Correct Answer:  B. Directly proportional to initial concentration
EXPLANATION

For a zero-order reaction, t₁/₂ = [A]₀/(2k), which is directly proportional to initial concentration.

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Q.57 Easy JEE Chemistry Chemical Kinetics
The rate of a chemical reaction is defined as the change in concentration of reactants or products per unit time. Which of the following is NOT a factor affecting reaction rate?
A Temperature of the system
B Nature of reactants and products
C Color of the reaction vessel
D Concentration of reactants
Correct Answer:  C. Color of the reaction vessel
EXPLANATION

The color of the reaction vessel does not affect the reaction rate. Temperature, nature of reactants, concentration, pressure, and catalyst are actual factors affecting reaction rate.

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Q.58 Medium JEE Chemistry Electrochemistry
A galvanic cell is constructed using Zn|Zn²⁺ and Cu|Cu²⁺ half-cells. If the concentration of Zn²⁺ is increased from 1 M to 10 M at 25°C, how does this affect the cell potential? (E°cell = 1.1 V)
A Decreases by 0.0296 V
B Increases by 0.0296 V
C Increases by 0.059 V
D Remains unchanged
Correct Answer:  A. Decreases by 0.0296 V
EXPLANATION

Using Nernst equation: Ecell = E°cell - (0.059/n)log(Q). Increasing [Zn²⁺] increases Q, making the log term positive, which decreases Ecell. ΔE = -(0.059/2)log(10) = -0.0295 ≈ -0.0296 V.

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Q.59 Medium JEE Chemistry Electrochemistry
During the electrolysis of molten NaCl using inert electrodes, if 2.3 g of Na is deposited at the cathode, what volume of Cl₂ gas (at STP) will be released at the anode?
A 2.24 L
B 1.12 L
C 4.48 L
D 0.56 L
Correct Answer:  B. 1.12 L
EXPLANATION

At cathode: Na⁺ + e⁻ → Na; moles of Na = 2.3/23 = 0.1 mol. At anode: 2Cl⁻ → Cl₂ + 2e⁻; for 0.1 mol Na, electrons = 0.1 mol, so Cl₂ moles = 0.1/2 = 0.05 mol. Volume at STP = 0.05 × 22.4 = 1.12 L.

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Q.60 Hard JEE Chemistry Electrochemistry
The molar conductivity of a strong electrolyte at infinite dilution (Λ°m) can be calculated using Kohlrausch's law. For NaCl, if Λ°m(HCl) = 426, Λ°m(NaOH) = 248, and Λ°m(KCl) = 150, then Λ°m(NaCl) is:
A 426 + 248 - 150
B 426 + 150 - 248
C 248 + 150 - 426
D 424 S·cm²/mol
Correct Answer:  B. 426 + 150 - 248
EXPLANATION

Kohlrausch's law: Λ°m(NaCl) = Λ°m(HCl) + Λ°m(KCl) - Λ°m(KOH) = 426 + 150 - 248 = 328 S·cm²/mol.

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