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SSC CGL / CHSL

SSC CGL & CHSL MCQ questions — Quantitative Aptitude, English, Reasoning, General Knowledge.

1,082 Q 4 Subjects 10th / Graduate
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Difficulty: All Easy Medium Hard 1081–1082 of 1,082
Subjects in SSC CGL / CHSL
Q.1081 Medium Reasoning Ability
Priya faces North. She turns 90° clockwise, then 45° counter-clockwise, then 135° clockwise. Finally, she turns 90° counter-clockwise. Which direction is she facing now?
A North-West
B East
C South
D South-West
Correct Answer:  C. South
EXPLANATION
Step 1: Initial Position and First Turn

Priya starts facing North. She turns 90° clockwise.

\[\text{North} + 90° \text{ clockwise} = \text{East}\]
Step 2: Second and Third Turns Combined

From East, she turns 45° counter-clockwise, then 135° clockwise.

\[45° \text{ counter-clockwise} - 135° \text{ clockwise} = -90° \text{ (net clockwise)}\]
\[\text{East} + 90° \text{ clockwise} = \text{South}\]
Step 3: Final Turn

From South, she turns 90° counter-clockwise.

\[\text{South} + 90° \text{ counter-clockwise} = \text{East}\]

Priya is now facing East, not South. However, if we verify the total rotation: North → 90° CW → 45° CCW → 135° CW → 90° CCW gives a net rotation of 90° clockwise from North, which is East.

Note: The given answer of South appears to be incorrect based on the step-by-step calculation. The correct answer should be East.

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Q.1082 Medium Reasoning Ability
Rahul starts from point A and walks 10 km towards the North. He then turns right and walks 15 km. After this, he turns left and walks 8 km. Finally, he turns right and walks 12 km to reach point B. What is his net displacement from point A in terms of direction?
A 27 km towards North-East
B 25 km towards East-North-East
C 23 km towards North-East
D 20 km towards East
Correct Answer:  A. 27 km towards North-East
EXPLANATION
Step 1: Establish Coordinate System and Track North-South Movement

Let point A be at origin (0, 0). North is positive y-direction, East is positive x-direction.

Starting position: (0, 0)

- Walks 10 km North: position becomes (0, 10)

- Turns right (now facing East) and walks 15 km: position becomes (15, 10)

- Turns left (now facing North) and walks 8 km: position becomes (15, 18)

- Turns right (now facing East) and walks 12 km: position becomes (27, 18)

\[\text{Final position B} = (27, 18)\]
Step 2: Calculate Net Displacement

The net displacement is the straight-line distance from point A to point B using the Pythagorean theorem.

\[\text{Displacement} = \sqrt{(27-0)^2 + (18-0)^2}\]
\[= \sqrt{27^2 + 18^2} = \sqrt{729 + 324} = \sqrt{1053}\]
\[= \sqrt{729 + 324} = \sqrt{1053} \approx 32.45 \text{ km}\]
Step 3: Determine Direction of Displacement

Find the angle from North towards East using trigonometry.

\[\tan(\theta) = \frac{\text{East component}}{\text{North component}} = \frac{27}{18} = \frac{3}{2} = 1.5\]
\[\theta = \arctan(1.5) \approx 56.3°\]

This means the displacement is approximately 56.3° East of

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