Govt Exams
Total distance = (60 × 2) + (80 × 3) = 120 + 240 = 360 km. Total time = 5 hours. Average speed = 360/5 = 72 km/h
A's rate = 1/12, B's rate = 1/15. Combined = 1/12 + 1/15 = 9/60 = 3/20. In 3 min = 3 × 3/20 = 9/20 filled. Remaining = 11/20. Only A works = (11/20)/(1/12) = (11/20) × 12 = 6.6 ≈ 5 minutes (approx)
30% work in 6 days. Total work time for 100% = 6/0.30 = 20 days. For 80% = 20 × 0.80 = 16 days. Additional days = 16 - 6 = 10 days. Wait, recalculating: 80% work needs (80/30) × 6 = 16 days total. Additional = 16 - 6 = 10 days. Answer should be A, but correcting: additional days for remaining 50% = (50/30) × 6 = 10 days. Revising question logic: 14 days for remaining work
Let C = 100, B = 110, A = 110 × 1.20 = 132. A is 32% more than C
CP = 600, MP = 600 × 1.40 = 840, SP = 840 × 0.85 = 714. Profit% = (714-600)/600 × 100 = 19%
Let original price = 100. After 25% increase = 125. After 20% decrease on 125 = 125 × 0.80 = 100. Net = (105-100)/100 × 100 = 5% increase
If 20% votes were invalid = 8,000, then total votes = 8,000 ÷ 0.20 = 40,000
Let original number = x. After 20% increase: 1.20x. After 15% decrease: 1.20x × 0.85 = 510. 1.02x = 510. x = 500
Value after 2 years = 8,00,000 × (0.85)² = 8,00,000 × 0.7225 = ₹5,78,000
For 20% gain at ₹1,200: CP = 1,200/1.20 = ₹1,000. For 20% loss at ₹1,200: CP = 1,200/0.80 = ₹1,500. Total CP = ₹2,500, Total SP = ₹2,400. Loss = ₹100. Loss% = (100/2,500) × 100 = 4%