Govt Exams
Q₁₀ = k(T+10)/k(T) = (6 × 10⁻²)/(3 × 10⁻²) = 2. For typical reactions, Q₁₀ = 2-3
Rate depends only on [A] (order = 1 w.r.t. A). Halving [A] decreases rate by factor of 2. [B] has no effect
The slowest step in a mechanism is the rate-determining step (RDS), which is step 2
0 = 0.5 - 0.02t; t = 0.5/0.02 = 25 s
Not all collisions are effective; only those with proper orientation and sufficient energy lead to reaction
Using ln(k₂/k₁) = (Eₐ/R)(T₂-T₁)/(T₁T₂); ln(2) = (Eₐ/8.314)(10/93000); Eₐ ≈ 50.4 kJ/mol
After 90 min = 3 half-lives, remaining = (1/2)³ = 1/8
Overall order = sum of exponents in rate law = 2 + 1 = 3 (third order)
For elementary reactions, the rate law is determined by the stoichiometry: Rate = k[A]²[B], as 2 A molecules and 1 B molecule participate
The pre-exponential factor accounts for collision frequency, proper orientation (steric factor), and the Maxwell-Boltzmann energy distribution of molecules