Placement Papers - MCQ Practice Questions

sin² θ + cos² θ = 1. ($\frac{3}{5}$)² + cos² θ = 1. cos² θ = 1 - $\frac{9}{25}$ = $\frac{16}{25}$. cos θ = $\frac{4}{5}$ (positive since acute).

Cost price = 100 × 5 = Rs. 500. Selling price = (80 × 8) + (20 × 3) = 640 + 60 = Rs. 700. Profit = 200. Profit % = ($\frac{200}{500}$) × 100 = 28%.

P = ($\frac{5}{8}$) × ($\frac{4}{7}$) = $\frac{20}{56}$ = $\frac{5}{14}$.

Dividing by 3: x² - 4x + 3 = 0. (x - 1)(x - 3) = 0. So x = 1 or x = 3.

Five consecutive even numbers: x, x+2, x+4, x+6, x+8. Average = (5x + 20)/5 = 24. 5x + 20 = 120. x = 20. Largest = 28.

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log₂ 8 means 2^x = 8. Since 2³ = 8, x = 3.

Circumference = 2πr. 44 = 2 × ($\frac{22}{7}$) × r. 44 = ($\frac{44}{7}$) × r. r = 7 cm.

(256)^($\frac{1}{4}$) = fourth root of 256 = 4 (since 4⁴ = 256).

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(x + 1/x)² = x² + 2 + 1/x². 25 = x² + 2 + 1/x². So x² + 1/x² = 23.

Average speed = Total distance / Total time = $\frac{240}{6}$ = 40 km/h

√144 = 12 because 12 × 12 = 144

TCS 2024-25 recruitment follows a multi-stage process: aptitude test, coding round (CodeVita style), technical interview, and HR interview

15% of 800 = ($\frac{15}{100}$) × 800 = 0.15 × 800 = 120

Students passed = 60% of 50 = 30. Students failed = 50 - 30 = 20

CI = P(1+r/100)^n - P = 1000(1.1)² - 1000 = 1210 - 1000 = Rs. 210

Let boat speed = b. Upstream speed = b-2, Downstream speed = b+2. 15/(b-2) + 25/(b+2) = 5. Solving gives b = 8 km/h

($\frac{75}{250}$) × 100 = 30%

Let A=2x, B=3x, C=5x. Sum = 10x = 100, so x=10. Therefore C = 5×10 = 50