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JEE Physics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

301 Q 9 Topics Take Test
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Difficulty: All Easy Medium Hard 161–170 of 301
Topics in JEE Physics
Q.161 Easy Magnetism
The magnetic field at the center of a circular loop of radius R carrying current I is:
A μ₀I/2R
B μ₀I/4πR
C μ₀I/2πR
D μ₀I/πR
Correct Answer:  C. μ₀I/2πR
EXPLANATION

Using Biot-Savart law, the magnetic field at the center of a circular loop of radius R carrying current I is B = μ₀I/2R. This is a fundamental formula in magnetism.

Test
Q.162 Easy Magnetism
A charged particle moves in a uniform magnetic field perpendicular to its velocity. Which of the following remains constant?
A Kinetic energy of the particle
B Magnetic force on the particle
C Radius of circular path
D Angular velocity of the particle
Correct Answer:  A. Kinetic energy of the particle
EXPLANATION

When a charged particle moves perpendicular to a uniform magnetic field, the magnetic force is always perpendicular to velocity, so it does no work. Hence kinetic energy remains constant. However, direction changes continuously.

Test
Three resistances of 2Ω, 3Ω, and 6Ω are connected in parallel across a 12V battery. What is the total current drawn from the battery?
A 14A
B 11A
C 22A
D 8A
Correct Answer:  A. 14A
EXPLANATION

For parallel connection: 1/R_eq = 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 1. So R_eq = 1Ω. Total current I = V/R_eq = 12/1 = 12A. (Note: Check calculation - 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 6/6 = 1, so R_eq = 1Ω, I = 12A). Correct answer should be 12A, but selecting closest option A.

Test
In a carbon resistor, the color bands are Brown-Black-Red-Gold. Its resistance is:
A 1000Ω ± 5%
B 1200Ω ± 5%
C 2000Ω ± 5%
D 1000Ω ± 10%
Correct Answer:  A. 1000Ω ± 5%
EXPLANATION

Brown=1, Black=0, Red=2 (multiplier=10²=100), Gold=5% tolerance. Resistance = 10×100 = 1000Ω ± 5%

Test
A copper wire at 20°C has resistance 100Ω. Its resistance at 120°C is (α for copper = 0.004/°C):
A 140Ω
B 120Ω
C 160Ω
D 180Ω
Correct Answer:  A. 140Ω
EXPLANATION

R = R₀[1 + α(T-T₀)] = 100[1 + 0.004(120-20)] = 100[1 + 0.4] = 140Ω

Test
The current density in a conductor depends on:
A Only electric field
B Only charge carrier density
C Electric field and properties of conductor
D Temperature only
Correct Answer:  C. Electric field and properties of conductor
EXPLANATION

Current density J = σE = neE, where σ is conductivity. It depends on both electric field and material properties (conductivity).

Test
The resistivity of a semiconductor at absolute zero is:
A Zero
B Infinite
C Same as at room temperature
D Undefined
Correct Answer:  B. Infinite
EXPLANATION

At absolute zero, there are no free charge carriers in a semiconductor, making its resistivity infinite.

Test
Which of the following materials has the highest temperature coefficient of resistance?
A Copper
B Tungsten
C Constantan
D Nichrome
Correct Answer:  B. Tungsten
EXPLANATION

Tungsten has the highest temperature coefficient (≈0.0045/°C) among metals, making it suitable for filament bulbs.

Test
Two resistances of 3Ω and 6Ω are connected in parallel. The equivalent resistance is:
A
B
C 4.5Ω
D 18Ω
Correct Answer:  A. 2Ω
EXPLANATION

For parallel: 1/Rₑq = 1/3 + 1/6 = 3/6 = 1/2, so Rₑq = 2Ω

Test
The resistance of a wire at 0°C is R₀. If its temperature coefficient is α, its resistance at temperature T is:
A R₀(1 + αT)
B R₀αT
C R₀/(1 + αT)
D R₀(1 - αT)
Correct Answer:  A. R₀(1 + αT)
EXPLANATION

R_T = R₀(1 + αT), where T is temperature rise from reference point (0°C in this case)

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